Find force to push block up incline with static and kinetic friction in certain time

In summary, the problem involves a box at rest on a ramp with a length of 8.76 and incline of 30 degrees. The coefficients of kinetic and static friction are given. The task is to find the constant force needed to push the box up the ramp in 4.45 seconds. The solution involves calculating the acceleration and using the sum of forces equation. The velocity and acceleration calculations need to be redone.
  • #1
hairE
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Homework Statement


A 5.03 box sits at rest at the bottom of a ramp that is 8.76 long and that is inclined at 30.0 above the horizontal. The coefficient of kinetic friction is 0.40, and the coefficient of static friction is 0.50.

What constant force , applied parallel to the surface of the ramp, is required to push the box to the top of the ramp in a time of 4.45 ?

Homework Equations


max mu_static * force Normal = Force to budge Block
mu_kinetic * force Normal = Force Friction



The Attempt at a Solution



The force to overcome the static friction is what is confusing me.
To start: Find acceleration.
8.76m / 4.45 s = 1.969 m/s = veloc.
1.969 m/s /4.45 s = .4425 m/s^2 = accel.

F= ma = 5.03*.4425 = 2.225 N = Leftover, or net force to keep the block accelerating up the ramp

(Parallel to plane) ƩF= Push - Force static - force kinetic - Weight = 2.25N
2.25N = Push - mgsin(30) - (mu_k)mgcos(30) - (mu_s)mgcos(30)

BUT*** Force static is only acting until the object budges. And the question is asking for a CONSTANT force applied. I'm confused. PLEASE help! I just need the sum of forces explained to me.
 
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  • #2


hairE said:
(Parallel to plane) ƩF= Push - Force static - force kinetic - Weight = 2.25N
2.25N = Push - mgsin(30) - (mu_k)mgcos(30) - (mu_s)mgcos(30)
Either static or kinetic friction acts--not both (at the same time).

Since the object is moving, use kinetic friction. (Will the calculated force be enough to overcome static friction?)
 
  • #3


Hi HairE
hairE said:
8.76m / 4.45 s = 1.969 m/s = veloc.

Are you clear as to what velocity you just calculated? Is it the velocity at some particular time during the motion or is it the overall average velocity? With that in mind, are you sure you calculated the acceleration correctly?
 
  • #4


Oops... TSny is right.
hairE said:
To start: Find acceleration.
8.76m / 4.45 s = 1.969 m/s = veloc.
1.969 m/s /4.45 s = .4425 m/s^2 = accel.
You'll need to redo this calculation. (In addition to what I already pointed out.)
 
  • #5


Humm. If the coefficient of static friction is higher than the kinetic friction presumably you have to apply a force at least strong enough to get it moving. Then check that force gets it up the ramp quick enough. If not then even more force is required.
 

Related to Find force to push block up incline with static and kinetic friction in certain time

1. What is static and kinetic friction?

Static friction is the force that opposes the motion of an object when it is at rest. Kinetic friction is the force that opposes the motion of an object when it is in motion. Both types of friction are caused by the contact between two surfaces.

2. How do you calculate the force required to push a block up an incline?

To calculate the force required, you will need to consider the weight of the block, the angle of the incline, and the coefficients of static and kinetic friction between the block and the surface it is on. You can use the formula F = mg(sinθ + μcosθ), where F is the force required, m is the mass of the block, g is the acceleration due to gravity, θ is the angle of the incline, and μ is the coefficient of friction.

3. What is the difference between static and kinetic friction in this scenario?

The main difference between static and kinetic friction in this scenario is that static friction is the force needed to overcome the initial resistance and start the motion of the block, while kinetic friction is the force needed to keep the block in motion once it has started moving.

4. How does the time affect the force required to push the block up an incline?

The time does not directly affect the force required to push the block up an incline. However, the longer the block takes to reach the top of the incline, the more work is being done against friction, which means a greater force will be required to maintain the block's motion.

5. What factors can affect the coefficient of friction in this scenario?

The coefficient of friction can be affected by several factors, including the nature of the surfaces in contact, the roughness of the surfaces, and the presence of any lubricants or other substances between the surfaces.

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