- #1
matxjos
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Homework Statement
A 0.125kg basketball is rolling w/out slipping on a horizontal table at 4.50 m/s when it rolls off the edge and it falls to the floor, 1.10 m below. What is the rotational kinetic energy of the ball right before hitting floor?
Homework Equations
KE rot: .5 I w^2
KE translational: .5 m v^2
PE: mgh
The Attempt at a Solution
Initial: I figured out KE translational and PE for the initial conditions on the horizontal surface, these are easy.
I do not know how to get K rotational energy!
Final: I used vertical constant acceleration equations to find the final velocity. Then I got the kinetic energy right before hitting the floor. Potential energy is 0.
No idea how to get K rot energy!
I've been working on this problem forever (all morning). The answer to the problem is apparently 0.506J.
HOW?!
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