- #1
pardesi
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Question:
At the bottom of a glas bath lies a mirror covered by 20cm of water.In the air,30 cm above the water there hangs a lamp.Find the distance from the mirror at which an observer looking into the water will see the image of the lamp in the mirror
Relevant Formula:
apparent shift [tex]\Delta t=t(\frac{\mu}{1}-1)[/tex]
Attempt:
the apparent shift of the lamp is 10 cm so the situation is same as a lamp placed in the system without water at a distance of 60cm from the mirror.
But that's all i could get i don't understand the question well .
At the bottom of a glas bath lies a mirror covered by 20cm of water.In the air,30 cm above the water there hangs a lamp.Find the distance from the mirror at which an observer looking into the water will see the image of the lamp in the mirror
Relevant Formula:
apparent shift [tex]\Delta t=t(\frac{\mu}{1}-1)[/tex]
Attempt:
the apparent shift of the lamp is 10 cm so the situation is same as a lamp placed in the system without water at a distance of 60cm from the mirror.
But that's all i could get i don't understand the question well .