- Thread starter
- #1

#### coolbeans33

##### New member

- Sep 19, 2013

- 23

^{2}e

^{x}

the answer is f'(x)=(x

^{2}+ 2x)e

^{x}but I don't understand how to get there.

Also I need to find g'(x) if g(x)=sqrtx(e

^{x})

would the answer for the second one be .5x

^{-1/2}e

^{x}?