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#### xyz_1965

##### Member

- Jul 26, 2020

- 81

Here is the set up.

To find AC:

cos (60°) = AC/12

To find BC:

sin (60°) = BC/12

Is this correct?

- Thread starter xyz_1965
- Start date

- Thread starter
- Banned
- #1

- Jul 26, 2020

- 81

Here is the set up.

To find AC:

cos (60°) = AC/12

To find BC:

sin (60°) = BC/12

Is this correct?

- Jan 30, 2018

- 428

Hopefully, you will soon have enough confidence in yourself that you won't need to ask questions like these!

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- Jul 26, 2020

- 81

I hope to get there soon. I found a few questions that I am stuck with in terms of a geometric figure. I will post each question later. I simply need help setting it up. If you can provide me with a picture, a visual of the situation, that would be so cool and helpful.

Hopefully, you will soon have enough confidence in yourself that you won't need to ask questions like these!