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Correct!So if x=0, it would then be -2f = 5f^2
At this point, either f= 0 or we can divide both sides by f.Correct!
But bear in mind that we are asked to find the real values of $f$. So now we have the quadratic equation in terms of $f$, i.e.
$-2f = 5f^2$
or
$ 5f^2+2f=0$
do you know how to solve this quadratic equation for $f$?