- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
$\triangle ABC$ (with side length $a,b,c$)
given :
$(1)\angle A=60^o$
$(2)$ the area of $\triangle ABC=10\sqrt 3$
$(3) a^2+b^2+c^2=138$
please find :$a+b+c=?$
given :
$(1)\angle A=60^o$
$(2)$ the area of $\triangle ABC=10\sqrt 3$
$(3) a^2+b^2+c^2=138$
please find :$a+b+c=?$