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- Feb 14, 2012

- 3,676

Find \(\displaystyle a+b+c\).

- Thread starter anemone
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- Thread starter
- Admin
- #1

- Feb 14, 2012

- 3,676

Find \(\displaystyle a+b+c\).

- May 31, 2013

- 118

\(\displaystyle 8x^3-3x^2-3x-1=0\)

\(\displaystyle 9x^3=(x+1)^3\)

\(\displaystyle 9=(1+\frac{1}{x})^3\)

\(\displaystyle x=\frac{1}{\sqrt[3]{9}-1}\)

by factorizing,

\(\displaystyle a=81,b=9,c=8\)

\(\displaystyle a+b+c=98\)

\(\displaystyle 9x^3=(x+1)^3\)

\(\displaystyle 9=(1+\frac{1}{x})^3\)

\(\displaystyle x=\frac{1}{\sqrt[3]{9}-1}\)

by factorizing,

\(\displaystyle a=81,b=9,c=8\)

\(\displaystyle a+b+c=98\)

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