- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
a,b,c,d are four roots of equation :
(x-2)(x+1)(x+4)(x+7)-19=0
and a<b<c<d
find : 2d-2c
(x-2)(x+1)(x+4)(x+7)-19=0
and a<b<c<d
find : 2d-2c
$(x-2)(x+1)(x+4)(x+7)-19 = x^4+10x^3+15x^2-50x-75 = (x^2+5x+5)(x^2+5x-15).$a,b,c,d are four roots of equation :
(x-2)(x+1)(x+4)(x+7)-19=0
and a<b<c<d
find : 2d-2c