Faster than light in Quantum mechanics?

In summary: In optics and electromagnetism, vp is the phase velocity of an electromagnetic wave traveling through a material medium. Substituting the value into vpv = c2 of de Broglie theory, v=108c should be much faster than light speed c in vacuum?
  • #1
stgdf01
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In <Engineering Electromagnetics> written by W.H.Hayt and J.A.Buck( 6th edition,McGraw-Hill,p372), the phase velocity vp of electromagnetic waves in copper at 60Hz (commercial electric power) is 3.2m/s. Substituting the value into vpv = c2 of de Broglie theory, v=108c should be much faster than light speed c in vacuum?
 
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  • #2
Hi stgdf01 and welcome to the forum,

The analysis you posted sounds incorrect. Phase velocity (of the EM wave) must always be greater or equal to c. The analysis seems to have been done with the assumption that the AC voltage wave represents the actual movement of energy. It doesn't. The energy travels far quicker than the swinging of the voltage. But maybe the person doing the analysis meant the velocity of the conduction current? If so, then group velocity vg rather than phase velocity is the correct term to use.

vp vg= c2
 
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  • #3
PhilDSP said:
The analysis you posted sounds incorrect. Phase velocity (of the EM wave) must always be greater or equal to c. The analysis seems to have been done with the assumption that the AC voltage wave represents the actual movement of energy. It doesn't. The energy travels far quicker than the swinging of the voltage.

The study to vp in conductors is based on first principle(Maxwell's equations) and has nothing to do with parameters in circuit theory such as voltage,inductance and capacitance. For example, J.D.Jackson's <Classical Electrodynamics> and D.J.Griffiths's <Introduction to Electrodynamics>.



PhilDSP said:
If so, then group velocity vg rather than phase velocity is the correct term to use.

vp vg= c2


The group velocity vg=dw/dk of low-frequency electromagnetic field in conductors is twice as much as vp=w/k (P.Lorrain, D.R.Corson, F.Lorrain, <Electromagnetic Fields and Waves>, 3rd edition). For commercial power in copper, vp=3.2m/s and vg=6.4m/s. In this case, neither vp nor vg can play the role of c2/vp in de Broglie's theory. Actually, it is v=p/m (m=E/c2) in point mechanis.
 
  • #4
stgdf01 said:
In this case, neither vp nor vg can play the role of c2/vp in de Broglie's theory.

It sounds likely that the analysis involved integration over macroscopic areas of space and large increments of time. In that case the average variation of the EM values would have washed out the high frequency effects. That's what I was trying to express in the first response. The analysis apparently ignores quantum effects.
 
  • #5
stgdf01 said:
Substituting the value into vpv = c2 of de Broglie theory, v=108c should be much faster than light speed c in vacuum?

This result of de Broglie theory is usually explicitly derived for matter waves. You will of course get strange results when you try to use it without proper modification for particles without rest mass and em waves.
 
  • #6
neutrinos as being said faster than light,,have very small mass and could be compound of gravity also accelerating speed such as dark energy particles..therefore interacting with light much like gravity does..as a mediator..a boson wave..already there..QED
 
  • #7
Cthugha said:
This result of de Broglie theory is usually explicitly derived for matter waves. You will of course get strange results when you try to use it without proper modification for particles without rest mass and em waves.



E=hw and p=hk is of course tenable to photons otherwise the Compton effect, photoelectric effect, blackbody radiation and others cannot be interpreted. In history, these two relations are concluded from experiments to massless photons and then de Broglie extended to massive matter waves(electrons,say).
 
  • #8
stgdf01 said:
E=hw and p=hk is of course tenable to photons[...]

Sure, but that does not have anything to do with [tex]v_p v=c^2.[/tex] This result is derived explicitly in the nonrelativistivc limit for matter waves and requires w and p to depend on mass. Some good textbooks on this topic state this explicitly. Even the really basic about about basic knowledge for engineers by Hennecke mentions this.
 
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  • #9
Cthugha said:
Sure, but that does not have anything to do with [tex]v_p v=c^2.[/tex] This result is derived explicitly for matter waves and requires w and p to depend on mass. Almost every good textbook on this topic states this explicitly. Even the really basic about about basic knowledge for engineers by Hennecke mentions this.

Actually the history behind that for waves in general extends much further back in time:

The idea of a group velocity distinct from a wave's phase velocity was first proposed by W.R. Hamilton in 1839, and the first full treatment was by Rayleigh in his "Theory of Sound" in 1877.[6]

http://en.wikipedia.org/wiki/Group_velocity
http://en.wikipedia.org/wiki/John_William_Strutt,_3rd_Baron_Rayleigh
 
  • #10
Cthugha said:
Sure, but that does not have anything to do with [tex]v_p v=c^2.[/tex] This result is derived explicitly in the nonrelativistivc limit for matter waves and requires w and p to depend on mass. Some good textbooks on this topic state this explicitly. Even the really basic about about basic knowledge for engineers by Hennecke mentions this.


But in optics and electromagnetism, [tex]v_p v=c^2.[/tex] is still valid to a field(photons) in vacuum. On the other hand, the photon can be described in relativistic mechanics as a special case of V=c and [tex]m_0=0[/tex]
 
  • #11
PhilDSP said:
It sounds likely that the analysis involved integration over macroscopic areas of space and large increments of time. In that case the average variation of the EM values would have washed out the high frequency effects. That's what I was trying to express in the first response. The analysis apparently ignores quantum effects.

I regards this as a counter-example of [tex]v_p v_g=c^2[/tex],although [tex]v_p v=c^2[/tex] is universal.That is to say, the group velocity vg is not always equal to V. It can be applied to explain why those experiments of superluminal group velocities vg>c are not really faster than light v>c.
 
  • #12
stgdf01 said:
But in optics and electromagnetism, [tex]v_p v=c^2.[/tex] is still valid to a field(photons) in vacuum.

Yes, in vacuum. You were interested in light in a material, no?

stgdf01 said:
On the other hand, the photon can be described in relativistic mechanics as a special case of V=c and [tex]m_0=0[/tex]

You can treat a photon as having [tex]m_0=0[/tex] if you include the full relativistic mass [tex]E=\sqrt{(m_0 c^2)^2 +(p c)^2}[/tex] in the derivation.

However, you get the [tex]v[/tex] in [tex]v_p v=c^2[/tex] in common de Broglie theory by using [tex]p=m v[/tex]. For photons you do not have this explicit dependence and just use [tex]p=\frac{h}{\lambda}[/tex], so you only arrive at the trivial [tex]v_p =\frac{c}{n}.[/tex]
 
  • #13
If we know or can determine the dispersion equation (which doesn't include a mass term) then we can find the phase velocity algebraically and the group velocity by taking the derivative of the dispersion equation (or its roots) with respect to wave number.

[tex] v_p = \frac {\omega}{k} \ \ \ \ \ \ v_g = \frac {\partial \omega}{\partial k}[/tex]

For example: the FT of [itex]\ \ \ (\nabla^2 - \frac {1}{c^2} \frac {\partial^2}{\partial t^2}) \phi = 0 \ \ \ [/itex] is [itex]\ \ \ (-k^2 + \frac {\omega^2}{c^2}) \phi = 0 \ \ \ [/itex] so that [itex]\ \ \ D(\omega, k) = -k^2 + \frac {\omega^2}{c^2}[/itex]

then [itex] \ \ \ \ \omega = ±ck \ \ \ \ [/itex] giving [itex] \ \ \ \ v_p = ±c \ \ \ \ [/itex] and [itex] \ \ \ \ v_g = ±c \ \ \ \ [/itex]
 
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Related to Faster than light in Quantum mechanics?

1. What is the concept of "faster than light" in quantum mechanics?

In quantum mechanics, the concept of "faster than light" refers to the idea that, at the quantum level, particles can move and interact with each other instantaneously, without any time delay. This is in contrast to the speed limit imposed by the theory of relativity, which states that nothing can travel faster than the speed of light.

2. Is it possible for particles to travel faster than light in quantum mechanics?

No, it is not possible for particles to travel faster than light in quantum mechanics. While quantum mechanics does allow for instantaneous interactions between particles, this does not violate the speed limit set by the theory of relativity, as no actual movement is occurring.

3. How does quantum entanglement relate to the concept of "faster than light"?

Quantum entanglement is a phenomenon in which two or more particles become connected in such a way that the state of one particle affects the state of the other(s), regardless of the distance between them. This instantaneous connection may seem like "faster than light" communication, but it does not actually violate the speed limit of light as no information is being transmitted between the particles.

4. Can quantum tunneling be considered a form of "faster than light" movement?

While quantum tunneling does involve particles seemingly "passing through" barriers instantaneously, it is not considered a form of "faster than light" movement. This is because the particles are not actually traveling faster than light, but rather utilizing their quantum nature to pass through the barrier.

5. Could the discovery of particles traveling faster than light in quantum mechanics have any implications for our understanding of the universe?

The discovery of particles traveling faster than light in quantum mechanics would have significant implications for our understanding of the universe and would likely require a major overhaul of our current theories. It would also raise questions about the nature of space and time, and how they are affected by the quantum realm.

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