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Ahmedemad22
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OP warned about not using the homework template
Can anyone help me on this problem from this video starting from 8:03 , I've been working on it for a week ,and I couldn't find a solution.
Correct. What would happen if he didn'tAhmedemad22 said:I think he used his timer to apply force to the ruler
##Mv^2/l=mg\cos x-n\sin x\ ##: in ##\ mv^2\over 2\ ## I see some energy. In ##\ mgl\cos x\over 2\ ## also. But the other one ? Perhaps it's good to set up a list of known/unknown variables and a few more equations -- all of these important constituents of the template !Ahmedemad22 said:Describing normal force from the floor.
Do you have a ruler and a reasonably smooth surface nearby ?Ahmedemad22 said:Maybe, ruler wouldn't slide , correct?
What is ##nl\sin x\over 2 ## ?Ahmedemad22 said:can you explain further?
and did you observeAhmedemad22 said:Yes , I have made that experiment twice.
as correct or as proven wrong ?Ahmedemad22 said:Maybe, ruler wouldn't slide , correct?
gravity is one componentAhmedemad22 said:what makes the centripetal force to the center of the mass
How do you now ?Ahmedemad22 said:It wouldn't slide if he didn't put the timer.
'it' being 'blocked the foot of the ruler from sliding to the left' (while the ruler is falling to the right) ?Ahmedemad22 said:And it slided when i did it
NoAhmedemad22 said:It wouldn't slide if he didn't put the timer. And it slided when i did it
Yes. So you reproduced Walters result.Ahmedemad22 said:I pushed the ruler a bit and it started to fall then it's gone away from the block i put behind it , and slided until it lied at the surface
Yes, Walter said it was more complicated. And no, there does not seem to be a worked out solution within google range. We have to think for ourselvesAhmedemad22 said:This problem is more trickier for me , I even tried to search about it but i didn't find anything helpful
In my case the bottom end of the ruler (that is falling to the right) slides to the left, already when theta is about 30 degrees.Ahmedemad22 said:It slided also but only when it lied at the ground
It certainly can. That's why the block is needed -- for the horizontal componentAhmedemad22 said:can a force which is applied from the pivot point make a radial acceleration?
That's the vertical component and the normal force works outwards, but: yesAhmedemad22 said:i.e the normal force from the surface that touches the pivot point
No. The ruler is not just translating but also rotating. So more complicated than the girl on the igloo: there is a rotational energy term too.Ahmedemad22 said:So Mv2/l=mg cos(x) ?
Ahmedemad22 said:And does normal force from the block does torque?I don't understand why we need opposite torque
The "Falling Ruler Problem" is a physics problem that involves balancing a ruler on its end and predicting how long it will take for the ruler to fall over.
The solution shown in the video at 8:03 involves using the principle of conservation of energy to calculate the time it will take for the ruler to fall over.
There are multiple ways to get help with the "Falling Ruler Problem", including consulting with a physics teacher or tutor, participating in online forums or discussion groups, or seeking out resources such as textbooks or online tutorials.
Some common mistakes when attempting to solve the "Falling Ruler Problem" include not properly accounting for all forces acting on the ruler, not understanding the concept of torque, and not using the correct equations or units in calculations.
Understanding the "Falling Ruler Problem" can help students develop critical thinking and problem-solving skills, gain a better understanding of physics concepts such as forces and energy, and apply these concepts to real-world situations.