Falling Elevator - Projectiles

In summary, the path of a ball projected at an angle to the horizontal in a falling elevator would be parabolic, regardless of the reference frame being accelerated. This can be seen by working out the problem in an inertial frame and from the point of view of someone falling with the lift. In free fall, the path of a ball would be parabolic, as demonstrated by the "vomit" airplane used for astronaut training. If the ball is released without any initial velocity, it would appear stationary from the reference frame of the person in free fall. However, if given an initial velocity, the ball would move in a straight line with a constant velocity relative to the person in free fall.
  • #1
PFuser1232
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20
What would be seen if a ball were projected at an angle to the horizontal in a falling elevator? Would the path be parabolic as always? And why?
 
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  • #2
Try working out the problem in an inertial frame, and then working out what happens from the POV of someone falling with the lift.

Or another way: you have heard of "free fall" right?
What happens to ball's thrown in free fall?
 
  • #3
Simon Bridge said:
Try working out the problem in an inertial frame, and then working out what happens from the POV of someone falling with the lift.

Or another way: you have heard of "free fall" right?
What happens to ball's thrown in free fall?

The path would be parabolic whether or not the reference frame was accelerated?
 
  • #4
MohammedRady97 said:
The path would be parabolic whether or not the reference frame was accelerated?

Hint: The "vomit" airplane that astronauts practice into simulate zero-g is an airplane in free-fall.

So think again, what do you think the path should look like?

Zz.
 
  • #5
MohammedRady97 said:
The path would be parabolic whether or not the reference frame was accelerated?
Imagine you released a ball from your hand while in that free falling elevator. What would happen?
 
  • #6
Doc Al said:
Imagine you released a ball from your hand while in that free falling elevator. What would happen?

From my reference frame the ball would be stationary.
 
  • #7
MohammedRady97 said:
From my reference frame the ball would be stationary.
Good! Now what happens if you gave it an initial velocity?
 
  • #8
Doc Al said:
Good! Now what happens if you gave it an initial velocity?

It would simply move in a straight line.
 
  • #9
MohammedRady97 said:
It would simply move in a straight line.
Yep.
 
  • #10
So the velocity of the ball relative to me would be constant?
 
  • #11
MohammedRady97 said:
So the velocity of the ball relative to me would be constant?
That's correct.
 
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Related to Falling Elevator - Projectiles

1. What is a falling elevator projectile?

A falling elevator projectile is an object that is launched or dropped from a stationary or moving elevator. It is affected by gravity and follows a parabolic path as it falls to the ground.

2. How does gravity affect a falling elevator projectile?

Gravity is the force that pulls objects towards the center of the Earth. As a falling elevator projectile is launched or dropped, gravity causes it to accelerate towards the ground at a rate of 9.8 meters per second squared.

3. What factors affect the trajectory of a falling elevator projectile?

The trajectory of a falling elevator projectile is affected by the initial velocity, the angle at which it is launched, and the force of gravity. Other factors such as air resistance and wind can also play a role in the path of the projectile.

4. How can we calculate the distance traveled by a falling elevator projectile?

The distance traveled by a falling elevator projectile can be calculated using the formula d = v0t + 1/2at2, where d is the distance traveled, v0 is the initial velocity, a is the acceleration due to gravity, and t is the time in seconds.

5. Is the path of a falling elevator projectile affected by the mass of the object?

No, the mass of the object does not affect the path of a falling elevator projectile. All objects, regardless of their mass, will fall towards the ground at the same rate due to the force of gravity.

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