# Trigonometryexpression sin^n(x)/(sin^n(x)+cos^n(x))

#### Vali

##### Member
Hi!
I have sin^n(x)/(sin^n(x)+cos^n(x))
The expression is the same with 1/(ctg^n(x)+1) and I have no idea how to get to this answer.
Can you help me?

#### MarkFL

##### Pessimist Singularitarian
Staff member
If you divide the numerator and denominator by $$\sin^n(x)$$ what do you get?

#### Vali

##### Member
1/[(sin^n(x)+cos^n(x))/sin^n(x)]
edit:
I get it.Thanks a lot!