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Homework Statement
Show that ##\Sigma \vec F = \frac {d \vec p}{dt} ##
Homework Equations
##\Sigma \vec F = m \vec a ##
## \vec a = \frac {d \vec v}{dt} ##
## \vec p = m \vec v ##
The Attempt at a Solution
We need to prove that ## \frac {d \vec p}{dt} = m \vec a ##. When I physicists correctly take the derivative of ## \vec p ##, they get ## m \vec a ##. How come taking the derivative doesn't affect ##m## ? If ##m## is constant, shouldn't it go to zero?
I know that I am wrong somewhere, but I want to fully understand how this formula was derived.
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