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- Thread starter CSmith
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- Jan 26, 2012

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What did you get for each term? There are two terms added together in this problem so doing each part separately will help us understand your thought process.32 2/5(on top of the 32)+64 2/3(on top of the 64. I got 7

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ok for the first part this is what i didWhat did you get for each term? There are two terms added together in this problem so doing each part separately will help us understand your thought process.

1.)(32 1/5)2(squared = 32 to the 5th power(

32x5=160 so i have to find the power to give me 160 which is 32x5. so 32x32x32x32x32=5 .i got 5 for that.

2nd part 2.) 64 2/3=(64 1/3)squared....64x3=192.then i have to ask what power gives me 192. and i got 96 squared.96x96 gives me my 192 so i put the power which is =2

5+2=7

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- Jan 26, 2012

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You start with \(\displaystyle 32^{\frac{2}{5}}\). The 2 means square 32 and the \(\displaystyle \frac{1}{5}\) or 5 in the bottom means find a number which multiplied by itself 5 times equals 32.ok for the first part this is what i did

1.)(32 1/5)2(squared = 32 to the 5th power(

32x5=160 so i have to find the power to give me 160 which is 32x5. so 32x32x32x32x32=5 .i got 5 for that.

2nd part 2.) 64 2/3=(64 1/3)squared....64x3=192.then i have to ask what power gives me 192. and i got 96 squared.96x96 gives me my 192 so i put the power which is =2

5+2=7

Your first idea was good. You tried to find \(\displaystyle 32^{\frac{1}{5}}\). To do that you need to find a number that when

Put another way, \(\displaystyle x^5 = x \cdot x \cdot x \cdot x \cdot x\)

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- Feb 5, 2012

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Hi CSmith,i squared the 32 and got 1024

Yes it's correct. You can do this problem in two ways.

1) Find \(32^{\frac{1}{5}}\) first and then square the answer to find \(32^{\frac{2}{5}}\).

2) Find \(32^{2}\) first and then take the fifth root. You have done the first part. Now what remains is to find a number \(x\) such that, \(32^{2}=1024=x^5\). Then \(x=32^{\frac{2}{5}}\)

Among these methods I think it would be easier to use the first method since \(32^{\frac{1}{5}}\) is easier to find than, \(1024^{\frac{1}{5}}\)

Kind Regards,

Sudharaka.

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- #7

Hi CSmith,

Yes it's correct. You can do this problem in two ways.

1) Find \(32^{\frac{1}{5}}\) first and then square the answer to find \(32^{\frac{2}{5}}\).

2) Find \(32^{2}\) first and then take the fifth root. You have done the first part. Now what remains is to find a number \(x\) such that, \(32^{2}=1024=x^5\). Then \(x=32^{\frac{2}{5}}\)

Among these methods I think it would be easier to use the first method since \(32^{\frac{1}{5}}\) is easier to find than, \(1024^{\frac{1}{5}}\)

Kind Regards,

Sudharaka.

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- #8

- Feb 5, 2012

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Thanks! after that what should i do?

I suggest that you review how to simplify fractional exponents and try to find the answer to your question along the methods described above. Some useful webpages are given below,can u show me an easiert method to do this sum please

1) Khan Academy

2) Math is Fun

3) The Math Page

Kind Regards,

Sudharaka.