- #1
imagemania
- 27
- 0
(This isn't homework)
I've been crating some notes, and noticed that we haven't been told one equation.
I know for:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} -\frac{b}{m} \frac{dx}{dt}[/tex]
I know the displacement is:
[tex] x = A \omega e^{-bt/2m} cos(\omega t+ \phi) [/tex]
[Ie damping]
I know for:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} -\frac{b}{m} \frac{dx}{dt} + \frac{F}{m}[/tex]
I know the displacement for this is:
[tex] x = Asin(\omega t + \phi) [/tex] (omega is for driving force).
But what about:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} + \frac{F}{m}[/tex]
I.e. No damping, what would x be for this?
Thank you!
[This is out of pure interest]
I've been crating some notes, and noticed that we haven't been told one equation.
I know for:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} -\frac{b}{m} \frac{dx}{dt}[/tex]
I know the displacement is:
[tex] x = A \omega e^{-bt/2m} cos(\omega t+ \phi) [/tex]
[Ie damping]
I know for:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} -\frac{b}{m} \frac{dx}{dt} + \frac{F}{m}[/tex]
I know the displacement for this is:
[tex] x = Asin(\omega t + \phi) [/tex] (omega is for driving force).
But what about:
[tex]\frac{d^2 x}{dt^2}[/tex] [tex] = \frac{-kx}{m} + \frac{F}{m}[/tex]
I.e. No damping, what would x be for this?
Thank you!
[This is out of pure interest]