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showing. Compute E(X)

I started this question with X=x

_{i}where i = 1,2,3 since there are 3 fair coins and there are either 1 2 or 3 heads that will show up. then it says that X will be the cube of the number of heads so I put

P(getting heads) = (1/2)^(i^3)

So E(X) = \(\displaystyle x

_{i}P(X=x

_{i})\) = \(\displaystyle i(1/2)^(i^3)\) summation from i=1 to 3..

am i on the right track??