# Evaluating Limits using L'Hospital (2)

#### shamieh

##### Active member
lim x--> 1
$$\displaystyle \frac{x^4 - 3x^3 + 3x^2 - x}{x^4 - 2x^3 + 2x - 1}$$

I got $$\displaystyle \frac{0}{6} = 0$$

#### MarkFL

Staff member
That's incorrect. Since you showed no work, I can't tell you where you went wrong. I will tell you I applied L'Hôpital's Rule 3 times to get the value of the limit.

#### shamieh

##### Active member
re did the problem, didn;t take the deriv properly in the denom. Did you get $$\displaystyle \frac{-1}{4}$$

#### MarkFL

Staff member
No, that's no what I got either (and I verified my result using a CAS). If you show your work, I can address where you are going wrong.

#### shamieh

##### Active member
wow I'm a idiot. I put 24 - 12 = 24.... -_-... I got $$\displaystyle \frac{1}{2}$$ .. correct?

#### MarkFL

wow I'm a idiot. I put 24 - 12 = 24.... -_-... I got $$\displaystyle \frac{1}{2}$$ .. correct?