- Thread starter
- #1

Just need someone to check my work.

\(\displaystyle

\int sec^4y \, tan^4y\)

\(\displaystyle \tan^4y * sec^2y * sec^2y \, dx\)

\(\displaystyle tan^4y * (1 + tan^2y) * sec^2y\)

\(\displaystyle u = tany\)

\(\displaystyle du = sec^2y\)

\(\displaystyle \int u^4 * (1 + u^2) * du\)

\(\displaystyle \int u^4 + u^6 * du\)

\(\displaystyle \frac{u^5}{5} + \frac{u^7}{7} + C\)

\(\displaystyle \frac{tan^5x}{5} + \frac{tan^7x}{7} + C\)