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Evaluate the Integral

shamieh

Active member
Sep 13, 2013
539
Can someone check my work?


\(\displaystyle
\int^4_0 \frac{6z + 5}{2z + 1} dz\)

\(\displaystyle \int^4_0 3 + \frac{2}{2z + 1} dz\)
\(\displaystyle
[3z + 2\ln|2z + 1|]^4_0 = 12 + 2\ln|9| \)
 

lfdahl

Well-known member
Nov 26, 2013
719
As far as I can see, you´ve done a great job - except for the factor 2 in front of ln|2z+1|
 

shamieh

Active member
Sep 13, 2013
539
the 2 cancels out with the 2z doesn't it? i think i see where i made my mistake
 

Prove It

Well-known member
MHB Math Helper
Jan 26, 2012
1,403
the 2 cancels out with the 2z doesn't it? i think i see where i made my mistake
$\displaystyle \begin{align*} \int{\frac{1}{a\,x + b} \, dx} = \frac{1}{a} \ln{ \left| a \, x + b \right| } + C \end{align*}$