Evaluate the integral (IIII)

[shamieh]

Evaluate the Integral.

Please help! I am so lost on this one!

\(\displaystyle \frac{x^2}{(4 - x^2)^\frac{3}{2}} \, dx\)

 

[Prove It]

Evaluate the Integral.

Please help! I am so lost on this one!

\(\displaystyle \frac{x^2}{(4 - x^2)^\frac{3}{2}} \, dx\)

The substitution [tex]\displaystyle \begin{align*} x = 2\sin{(\theta)} \implies dx = 2\cos{(\theta)}\,d\theta \end{align*}[/tex] will probably work...