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eurekameh
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v,escape = (2*mu/r)^(1/2), where mu = G*M. What I'm asking is if this page is wrong about calculating the escape velocity for the moon. They seem to have the equation wrong (missing 2 in front of mu = G*M,moon).
The escape velocity for the moon is the minimum speed that an object needs to reach in order to escape the moon's gravitational pull and enter into orbit around the moon.
The equation for calculating escape velocity on the moon is: v = √(2GM/R), where v is the escape velocity, G is the gravitational constant, M is the mass of the moon, and R is the radius of the moon.
No, the escape velocity equation for the moon is not wrong. However, there are factors such as atmospheric drag and the uneven distribution of mass on the moon that can affect the actual escape velocity.
The escape velocity for the moon is approximately 2,380 meters per second.
The escape velocity for the moon is much lower than the escape velocity for Earth. This is because the moon has less mass and a weaker gravitational pull compared to Earth.