Equations of motion ( vectors )

In summary, two particles are moving near the surface of the Earth with an acceleration of 10 m/s^2 towards the ground. They initially start at one point and move with velocities of 3m/s and 4m/s in opposite directions. The goal is to find the distance between the particles when their velocity vectors are mutually perpendicular. By considering a homogeneous gravitational field and the paths of the particles, it can be determined that their paths do not form a half-ellipse. Instead, after a certain time, the horizontal and vertical velocities of the particles can be used to derive a relation and solve for the distance between them when their velocity vectors are orthogonal.
  • #1
sambarbarian
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0

Homework Statement



Two particles move near the surface of the Earth with u. acc 10 m/s^2 towards the ground . At the initial moment , the particles were located at one point in space and moved with velocities 3m/s and 4 m/s in opposite directions . Find the distance between the particles when their velocity vectors are mutually perpendicular .

Homework Equations


s = ut + 1/2 at^2


The Attempt at a Solution



the trajectory of the particles should form a half - ellipse .

That's as far as i got , how should i relate the mutually perpendicular thing ??
 
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  • #2
the trajectory of the particles should form a half - ellipse .
No.
You can work with a homogeneous gravitational field here (same 10m/s^2 downwards everywhere). How do the paths look like? Can you write them as vectors?
 
  • #3
As they have the same origin and are moving in opposite directions , while one's velocity is greater under uniform gravitation , Their paths together should form a half ellipse . :/
 
  • #4
How does the path of the first object look like?
How does the path of the second object look like?

There is no way to combine them to a part of an ellipse, even if an ellipse can look a bit similar.
 
  • #5
so it will not form an ellipse , how should i solve this ?
 
  • #6
With the hints I gave in my posts?

After time t, what are the horizontal and vertical velocities of the objects?
What does "orthogonal" mean for vectors?
 
  • #7
Since there is no force in the horizontal direction,velocity changes only in the vertical direction.Assume after some time t they(velocity vectors) subtend some angles(α and β) with the horizontal.Since both the vectors should be perpendicular,derive a relation and solve.

Hope this hepls
 

Related to Equations of motion ( vectors )

1. What is an equation of motion in vectors?

An equation of motion in vectors is a mathematical representation of the relationship between an object's displacement, velocity, and acceleration in terms of vectors. It takes into account both the magnitude and direction of these quantities.

2. What are the three main equations of motion in vectors?

The three main equations of motion in vectors are the displacement equation (Δx = v0t + ½at²), the velocity equation (v = v0 + at), and the acceleration equation (v² = v0² + 2aΔx).

3. How do you use vectors to solve equations of motion?

Vectors are used to solve equations of motion by breaking down the quantities of displacement, velocity, and acceleration into their horizontal and vertical components. These components can then be added or subtracted using vector addition and subtraction rules to find the overall magnitude and direction of the quantities.

4. What is the significance of the constant acceleration assumption in equations of motion?

The constant acceleration assumption in equations of motion allows us to simplify the calculations and make them more manageable. It assumes that the object is moving with a constant acceleration throughout its motion, which may not always be the case in real-life scenarios.

5. Can equations of motion be used for non-linear motion?

No, equations of motion in vectors are only applicable to linear motion where the acceleration is constant. For non-linear motion, more complex equations, such as those involving calculus, are needed to accurately describe the motion of an object.

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