- #1
Wanderbiker
- 9
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I'm stuck on the solution of a problem. I'm looking for the general equation for the motion of a body with respect to time as follows:
A mass slides down a frictionless slope. The slope is not linear, but has the function y = -x^2 so that as the value of x increases, the acceleration (downward) increases.
The formula I came up with for the acceleration at any given (positive) value of x is:
a(x) = x * g * sqrt(1/(x^2 + 1/4)) where g is acceleration due to gravity.
I know that when acceleration is constant, velocity with respect to time is the integral of acceleration. Also, that position is the integral of velocity with respect to time.
What I'm having trouble with is the fact that velocy here depends not only on time, but also on position, since the slope is not linear.
Any help on this would be greatly appreciated.
Thanks
A mass slides down a frictionless slope. The slope is not linear, but has the function y = -x^2 so that as the value of x increases, the acceleration (downward) increases.
The formula I came up with for the acceleration at any given (positive) value of x is:
a(x) = x * g * sqrt(1/(x^2 + 1/4)) where g is acceleration due to gravity.
I know that when acceleration is constant, velocity with respect to time is the integral of acceleration. Also, that position is the integral of velocity with respect to time.
What I'm having trouble with is the fact that velocy here depends not only on time, but also on position, since the slope is not linear.
Any help on this would be greatly appreciated.
Thanks