Energy required to move an object to Earth's surface

In summary: Yes, that's correct. Since it does not result in 40R N that doesn’t help. So it looks like the given answer is simply wrong.Btw, the answer should specify the unit "Newtons", i.e. -20R N.
  • #1
songoku
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Homework Statement
Distance of an object from center of earth is twice the radius of earth and the gravitational force acting on it is 10 N. Find the energy required to move the object to earth's surface
Relevant Equations
##F=\frac{GMm}{r^2}##

##E_p=-\frac{GMm}{r}##
Energy required = ##\Delta E_p##
$$\Delta E_p = -\frac{GMm}{R}+\frac{GMm}{2R}$$
$$=-\frac{1}{2} \frac{GMm}{R}$$
$$=-\frac{1}{2} \frac{GMm}{R^2} R$$
$$=-\frac{1}{2} 40R$$
$$=-20R$$

But the answer key is 40R. Where is my mistake?

Thanks
 
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  • #2
I note the answer given is positive, suggesting it was supposed to be from a starting position inside the Earth. What do you get if you change "twice" to "half"?
 
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  • #3
haruspex said:
I note the answer given is positive, suggesting it was supposed to be from a starting position inside the Earth. What do you get if you change "twice" to "half"?
The object will be inside Earth initially so:
$$F=\frac{GMm}{R^3}r$$
$$10=\frac{GMm}{R^3}\left(\frac{1}{2}R\right)$$
$$\frac{GMm}{R^2}=20$$

The potential inside Earth :
$$V=-\frac{GM(3R^2 - r^2)}{2R^3}$$
$$=-\frac{GM(3R^2 - 0.25R^2)}{2R^3}$$
$$=-\frac{11}{8} \frac{GM}{R}$$

The potential energy inside Earth is ##-\frac{11}{8} \frac{GMm}{R}##

Energy required:
$$\Delta E_p=-\frac{GMm}{R}+\frac{11}{8} \frac{GMm}{R}$$
$$=\frac{3}{8} \frac{GMm}{R}$$
$$=\frac{3}{8} \frac{GMm}{R^2}R$$
$$=7.5R$$

Is this correct?

Thanks
 
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  • #4
songoku said:
The object will be inside Earth initially so:
$$F=\frac{GMm}{R^3}r$$
$$10=\frac{GMm}{R^3}\left(\frac{1}{2}R\right)$$
$$\frac{GMm}{R^2}=20$$

The potential inside Earth :
$$V=-\frac{GM(3R^2 - r^2)}{2R^3}$$
$$=-\frac{GM(3R^2 - 0.25R^2)}{2R^3}$$
$$=-\frac{11}{8} \frac{GM}{R}$$

The potential energy inside Earth is ##-\frac{11}{8} \frac{GMm}{R}##

Energy required:
$$\Delta E_p=-\frac{GMm}{R}+\frac{11}{8} \frac{GMm}{R}$$
$$=\frac{3}{8} \frac{GMm}{R}$$
$$=\frac{3}{8} \frac{GMm}{R^2}R$$
$$=7.5R$$

Is this correct?

Thanks
Yes, that's correct. Since it does not result in 40R N that doesn’t help. So it looks like the given answer is simply wrong.
Btw, the answer should specify the unit "Newtons", i.e. -20R N.
 
Last edited:
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  • #5
Thank you very much haruspex
 
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Related to Energy required to move an object to Earth's surface

1. What is the definition of "energy required to move an object to Earth's surface"?

The energy required to move an object to Earth's surface is the amount of work needed to overcome the force of gravity and bring the object from its initial position to the surface of the Earth. It is typically measured in joules (J) or kilojoules (kJ).

2. How is the energy required to move an object to Earth's surface calculated?

The energy required to move an object to Earth's surface is calculated using the formula E = mgh, where E is the energy in joules, m is the mass of the object in kilograms, g is the acceleration due to gravity (9.8 m/s^2), and h is the height (in meters) from the initial position to the surface of the Earth.

3. Does the energy required to move an object to Earth's surface depend on the mass of the object?

Yes, the energy required to move an object to Earth's surface is directly proportional to the mass of the object. This means that the more massive the object is, the more energy is required to move it to the surface of the Earth.

4. How does the height of the object affect the energy required to move it to Earth's surface?

The energy required to move an object to Earth's surface is directly proportional to the height of the object. This means that the higher the object is, the more energy is required to bring it down to the surface of the Earth.

5. Is the energy required to move an object to Earth's surface the same for all objects?

No, the energy required to move an object to Earth's surface will vary depending on the mass and height of the object. Heavier and taller objects will require more energy to be moved to the surface of the Earth compared to lighter and shorter objects.

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