Energy, momentum and centre of mass

In summary, the balls roll because the velocity of the CM is VCM=ωR where ω is the angular velocity.
  • #1
erisedk
374
7

Homework Statement


Two spheres, each of mass m and radius r are tied with a spring of spring constant k. The spring is stretched by a certain amount and the system is kept on a rough surface where friction is sufficient to prevent sliding. If one sphere is solid and the other is hollow, then for the spring-sphere system-
(A) Conservation of momentum is valid
(B) Conservation of energy is valid
(C) Displacement of centre of mass is not zero
(D) Velocity of centre of mass is zero

Multiple answers can be correct.

Homework Equations

The Attempt at a Solution


Since this is a rough surface with no sliding, friction will not act on the system because there will be pure rolling. Since net external force is zero, I think (A), (B) should hold.
Since net ext. force is zero, acceleration of centre of mass is also zero. Since velocity of COM before the system was released from rest was zero, and acc. of COM is zero, (D) should hold. And if velocity of COM is zero, (C) should also be true. But my answer is incorrect.
 
Physics news on Phys.org
  • #2
How do you conclude that the net external force is zero ?
 
  • #3
It would be helpful to know where and how the spring is attached to the spheres. If the direction of the force due to the spring is radial in reference to the spheres, then there should be no torque, thus rolling should not occur. (This is based on the first sentence of your attempt, I don't know if I understand your statement o0)).
 
  • #4
Second castro: I take it for granted from the problem formulation (or better: the solution attempt) that the spheres can roll towards and away from each other.
 
  • #5
Don't go by my solution attempt. I may be extremely wrong.
I view this as a spring-mass system in which there is movement of the masses due to stretching of the spring, however, instead of the masses sliding back and forth, they are rolling.
 
  • #6
Rolling around a horizontal axis that is perpendicular to the spring axis ?
 
  • #7
Something that looks like this--
 

Attachments

  • ggg.png
    ggg.png
    2.3 KB · Views: 357
  • #8
Anticlimactical and utterly unhelpful :)
But, never mind: assume the balls can't slide and can only roll. Driving force is the spring force that is equal and opposite for the two balls. Which one would accelerate more than the other ? Or would they have the same |a| (in the latter case I would say no to (c) and yes to (d) ) ?
 
  • #9
The solid sphere would accelerate more than the other one because it has a smaller moment of inertia. So, that rules out D. C should be true. B is definitely true. What about A (conservation of momentum)?
 
  • #10
How can the accelerations be different if the spring force is equal and opposite for the two spheres ?
And: doesn't (c) = true mean something for (a) ?
 
  • #11
BvU said:
How can the accelerations be different if the spring force is equal and opposite for the two spheres ?
Because the "f" in f=ma is net force. The force from the spring is not the only force in play here.
 
  • #12
Yeah, there's the friction that will provide a torque. This will result in a larger angular acceleration for the solid sphere cos it has a smaller MOI, which will lead to a larger linear acceleration (as a= rα for rolling).
Will momentum be conserved?
 
  • #13
Remember how the acceleration of the CM is related to the time derivative of the momentum.
 
  • #14
F(ext) = dP/dt.
The external force according to me should be zero as the same frictional force (and the same spring force) acts on both the bodies. So momentum should be conserved. But (A) is incorrect.
 
  • #15
erisedk said:
F(ext) = dP/dt.
The external force according to me should be zero as the same frictional force (and the same spring force) acts on both the bodies. So momentum should be conserved. But (A) is incorrect.

The spring force is the same, but why do you think the frictional forces are also the same. Remember, it is static friction in case of rolling.
 
  • #16
jbriggs444 said:
Because the "f" in f=ma is net force. The force from the spring is not the only force in play here.
Yes, thank you. ;) The question was intended to get Erise thinking in that direction...

Also somewhat spoiling is that erise already seems to know that (a) is false
 
  • #17
I don't know why the frictional forces should be different.
 
  • #18
erisedk said:
I don't know why the frictional forces should be different.
Step through these in turn:
Is the spring force the same on each?
Is the initial torque about their points of contact with the surface the same on each?
Is the initial angular acceleration the same for each?
Is the initial horizontal acceleration the same for each?
Is the net horizontal force the same for each?
 
  • #19
erisedk said:
I don't know why the frictional forces should be different.

The balls roll. In case of rolling, the velocity of the CM is VCM=ωR where ω is the angular velocity and R is the radius of the sphere. The same holds for the accelerations: a=Rα.
The friction f creates torque τ=Rf round the centre of the ball, Rf = I α. Because of rolling, a=Rα=f R2/I.
For the acceleration of the CM, you get ma=F(spring)-f . Eliminate f, and find the expression for the accelerations of both balls. The accelerations are proportional to the spring force, but depend also on the moments of inertia, which are not the same for both balls. The magnitude of accelerations are different: The centre of mass will accelerate.
 
  • #20
Oh ok! I get it now, thanks everybody :)
 

Related to Energy, momentum and centre of mass

What is energy?

Energy is the ability to do work or cause change in a system. It can exist in various forms such as kinetic, potential, thermal, chemical, and nuclear energy.

What is momentum?

Momentum is a quantity that describes an object's motion. It is defined as the product of an object's mass and velocity. In other words, it is the amount of force needed to stop an object's motion.

What is centre of mass?

The centre of mass is the point at which the entire mass of an object can be considered to be concentrated. It is the point around which an object's mass is evenly distributed, and it is the point where the object will balance.

How are energy and momentum related?

Energy and momentum are related through the principle of conservation of energy and momentum. This principle states that the total energy and momentum in a closed system remain constant. Therefore, if one form of energy changes, the corresponding change in momentum must also occur.

Why are energy, momentum, and centre of mass important in physics?

Energy, momentum, and centre of mass are important concepts in physics because they help us understand the behavior of objects and systems in motion. These concepts allow us to make predictions and calculations about the movement and interactions of objects, which are essential in many areas of science and engineering.

Similar threads

  • Introductory Physics Homework Help
Replies
23
Views
959
  • Introductory Physics Homework Help
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
9
Views
862
  • Introductory Physics Homework Help
2
Replies
55
Views
2K
  • Introductory Physics Homework Help
2
Replies
35
Views
2K
  • Introductory Physics Homework Help
Replies
10
Views
951
  • Introductory Physics Homework Help
2
Replies
44
Views
2K
  • Introductory Physics Homework Help
10
Replies
335
Views
8K
  • Introductory Physics Homework Help
2
Replies
40
Views
3K
Back
Top