- #1
davie08
- 115
- 0
Homework Statement
given:
2 H3PO4 + 3 Mg(OH)2 + 1427 kj → 6 H20 + Mg3(PO4)2
How much heat is involved if 927 grams of Mg(OH)2 reacts?
Homework Equations
The Attempt at a Solution
927 g x Mg(OH)2 mole/56.305g x 1427 kj/3Mg(OH)2 mole = 70,482 kj
I just felt like I did this wrong. Also how do I make the numbers small for showing the number of each element?