- #1
Pushoam
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Homework Statement
Modification: Take two big loops kept on both sides of the small loop at a distance a from the corresponding end of the small loop.
Homework Equations
The Attempt at a Solution
The flux through the bigger loop is equal to the flux through the smaller loop, provided that the current through the bigger loop is I.
Let's say that the current I is in the left bigger loop.
Then, the flux through the small loop = ##\frac { \mu_0 I a \ln 2 }{2 \pi}##
So, the emf is ξ = - ##\frac { \mu_0 ka \ln 2 }{2 \pi}##
Is this correct so far?