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- #1

#### veronica1999

##### Member

- Jun 4, 2012

- 63

It doesn't seem to be in the right form.

(x+2)^2 /5 + 2 (y-1)^2 = 1

I don't know what to do with the 2 in front of the (y-1)^2

Doesn't an ellipse have to be x^2/a^2 + y^2/b^2 = 1

- Thread starter veronica1999
- Start date

- Thread starter
- #1

- Jun 4, 2012

- 63

It doesn't seem to be in the right form.

(x+2)^2 /5 + 2 (y-1)^2 = 1

I don't know what to do with the 2 in front of the (y-1)^2

Doesn't an ellipse have to be x^2/a^2 + y^2/b^2 = 1

- Feb 5, 2012

- 1,621

Hi veronica1999,

It doesn't seem to be in the right form.

(x+2)^2 /5 + 2 (y-1)^2 = 1

I don't know what to do with the 2 in front of the (y-1)^2

Doesn't an ellipse have to be x^2/a^2 + y^2/b^2 = 1

Yes, an ellipse has its equation as, \(\displaystyle\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1\) if its major and minor axes coincides with the \(x\) and \(y\) axes of the Cartesian coordinate system. In this case the center point of the ellipse is at the origin. However a ellipse with its center point at, \((x_{0},y_{0})\) has an equation of the form,

\[\frac{(x-x_{0})^2}{a^2} + \frac{(y-y_{0})^2}{b^2} = 1\]

In your case the ellipse is centered at, \((-2,1)\). Now you should be able to draw your ellipse.

Kind Regards,

Sudharaka.

- Thread starter
- #3

- Jun 4, 2012

- 63

But I am still not sure what to do with the 2 in front of the (y-1)^2.

Could it have been a mistype meaning (y-1)^2/2 instead of 2(y-1)^2?

- Feb 5, 2012

- 1,621

Of course not. You can rearrange the equation by taking that \(2\) to the denominator like this,

But I am still not sure what to do with the 2 in front of the (y-1)^2.

Could it have been a mistype meaning (y-1)^2/2 instead of 2(y-1)^2?

\[\frac{(x+2)^2}{5} + \frac{(y-1)^2}{\frac{1}{2}} = 1\]

Is it clear to you now?

- Thread starter
- #5

- Jun 4, 2012

- 63

Yes!!!!

Thank you!!!

Thank you!!!

- Feb 5, 2012

- 1,621

You are welcome. I am glad to be of any help.Yes!!!!

Thank you!!!