# Element, venn diagram

#### Petrus

##### Well-known member
Calculate the number of elements in A1 U A2 U A3 if there are 97 elements in A1, 997 elements in A2 and 10098 elements in A3 in each of the following situations:
(a) The amounts are pairwise disjoint, i.e.
, too
.

(b)
.

(c) there are 10 elements in common for each pair of volumes and 4 elements common to all three sets.

(b)10098
(c) is the part I think I do wrong, will attach a picture of my venn diagram.
for some reason I get problem to attaché the picture but i get a1= 73, a2= 973, A3=10074 so the answer is (that is wrong I think) 73+10+10+10+4+10074+973

Last edited:

#### Klaas van Aarsen

##### MHB Seeker
Staff member
Calculate the number of elements in A1 U A2 U A3 if there are 97 elements in A1, 997 elements in A2 and 10098 elements in A3 in each of the following situations:
(a) The amounts are pairwise disjoint, i.e.
, too
.

(b)
.

(c) there are 10 elements in common for each pair of volumes and 4 elements common to all three sets.

(b)10098
(c) is the part I think I do wrong, will attach a picture of my venn diagram.
for some reason I get problem to attaché the picture but i get a1= 73, a2= 973, A3=10074 so the answer is (that is wrong I think) 73+10+10+10+4+10074+973
Hi Petrus!

Well, your (a) and (b) are right.
... so I guess we'll be waiting for your venn diagram...

#### Petrus

##### Well-known member
Hi Petrus!

Well, your (a) and (b) are right.
... so I guess we'll be waiting for your venn diagram...
Hello Serena,
I cant uppload my picture but I explained how it looks like

#### Klaas van Aarsen

##### MHB Seeker
Staff member
Hello Serena,
I cant uppload my picture but I explained how it looks like
A and B overlap with 10 elements in common.
The 3 sets together have 4 elements in common.

This doesn't quite seem to match what you have...

#### Petrus

##### Well-known member
A and B overlap with 10 elements in common.
The 3 sets together have 4 elements in common.

View attachment 706

This doesn't quite seem to match what you have...
Will it also be 6 on that A and C that you have not painted?

#### Klaas van Aarsen

##### MHB Seeker
Staff member
Will it also be 6 on that A and C that you have not painted?
Well, A and C would overlap in 10 elements and 4 of those elements are shared by all three.
So yes, it will also be 6 in the remaining overlap of A and C.

#### Petrus

##### Well-known member
Well, A and C would overlap in 10 elements and 4 of those elements are shared by all three.
So yes, it will also be 6 in the remaining overlap of A and C.
Basicly I have missunderstand the problem I thought it was 4 on a and b and c(that is correct) BUT its 10 on a and b... Thanks Sirena for help! I get the answer that is 11172

edit: after reading this again I notice how bad I explained. Basicly it was suposted to be 4 on a and b, when I calculated i calculated with 10 Unfortently im not a verry good explainer soo I hope this explain ok

Last edited:

#### Klaas van Aarsen

##### MHB Seeker
Staff member
Basicly I have missunderstand the problem I thought it was 4 on a and b and c(that is correct) BUT its 10 on a and b... Thanks Sirena for help! I get the answer that is 11172
Hmm, I get a different answer.
How did you find yours?

#### Petrus

##### Well-known member
Hmm, I get a different answer.
How did you find yours?
I get the rest 6 I can't uppload picture so I will just type what I get
10082+987+81+6+6+6+4=11172

97-6-4-6=81
997-6-4-4=987
10098-6-4-4=10082

Hope this give you a clue Thanks for the help aswell Serena!

#### Klaas van Aarsen

##### MHB Seeker
Staff member
997-6-4-4=987
This one doesn't seem quite right.

- - - Updated - - -

10098-6-4-4=10082
And this one has the right result, but a wrong number on the left hand side.

#### Petrus

##### Well-known member
This one doesn't seem quite right.

- - - Updated - - -

And this one has the right result, but a wrong number on the left hand side.
hmm? How can I get correct?:S (its a problem that you answer through internet and if you answer correct it says 'correct' and I got correct:S?)

#### Klaas van Aarsen

##### MHB Seeker
Staff member
I get the rest 6 I can't uppload picture so I will just type what I get
10082+987+81+6+6+6+4=11172

97-6-4-6=81
997-6-4-4=987
10098-6-4-4=10082

Hope this give you a clue Thanks for the help aswell Serena!
hmm? How can I get correct?:S (its a problem that you answer through internet and if you answer correct it says 'correct' and I got correct:S?)
They should be like this:
97-6-4-6=81
997-6-4-6=981
10098-6-4-6=10082

#### Petrus

##### Well-known member
They should be like this:
97-6-4-6=81
997-6-4-6=981
10098-6-4-6=10082
That give me also correct?! Are you serious? This is bad that I can get correct from both...? I will talk to my teacher about this because its not good if I get correct from miss calculated + doing a wrong step

#### Klaas van Aarsen

##### MHB Seeker
Staff member
I get the rest 6 I can't uppload picture so I will just type what I get
10082+987+81+6+6+6+4=11172

97-6-4-6=81
997-6-4-4=987
10098-6-4-4=10082

Hope this give you a clue Thanks for the help aswell Serena!
That give me also correct?! Are you serious? This is bad that I can get correct from both...? I will talk to my teacher about this because its not good if I get correct from miss calculated + doing a wrong step
I don't understand what you mean, but your end result should be:
10082+981+81+6+6+6+4=11166

#### Petrus

##### Well-known member
I don't understand what you mean, but your end result should be:
10082+981+81+6+6+6+4=11166
What I mean is that this is a problem I get from a program. We are supposed to write the answer and it says if its correct or wrong, I get correct from my 'wrong answer' and the correct answer. Thanks to you I know what I did wrong and the correct answer...