- #1
Snape1830
- 65
- 0
An iron arrowhead has an initial charge of 2.100e-6 C. How many electrons are required to give it a charge of −2.82 μC?
I know that e (the elementary charge) = +/- 1.602E-19 C
And N is the number (or excess charge)
I tried solving this problem 2 ways. The first way:
(2.100E-6 - 2.82E-6)/1.602E-19
I got 4.45E12 electrons
The second way I did:
2.100E-6-1.602E-19 * N = -2.82E-6
-1.602E-19 * N = -2.82E-6 - 2.100E-6
N =-4.92E6/-1.602E19
N= 3.05E25 electrons
However, my homework says it's wrong I tried typing them in with a negative sign, it's wrong. I tried rounding to the nearest electrons, still wrong.
What am I doing wrong? I really have no idea!
I know that e (the elementary charge) = +/- 1.602E-19 C
And N is the number (or excess charge)
I tried solving this problem 2 ways. The first way:
(2.100E-6 - 2.82E-6)/1.602E-19
I got 4.45E12 electrons
The second way I did:
2.100E-6-1.602E-19 * N = -2.82E-6
-1.602E-19 * N = -2.82E-6 - 2.100E-6
N =-4.92E6/-1.602E19
N= 3.05E25 electrons
However, my homework says it's wrong I tried typing them in with a negative sign, it's wrong. I tried rounding to the nearest electrons, still wrong.
What am I doing wrong? I really have no idea!