Electrostatic potential and velocity

[ryukyu]

Homework Statement

Point A is at an electrostatic potential of +1V relative to point B in a vacuum. An electron initially at rest at B moves to A. What is its velocity in m/s?

Homework Equations

E = PE + KE
PE= J/q * q
KE = 0.5 mv^2 (where v = velocity)

The Attempt at a Solution

Based on the definiton of an electron volt (eV), the energy of the electron is 1eV or 1.6E-19 Joules.

In solving the first equation:
1.6E-19 J = 1 J/C * e- + 0.5mv^2
e-= 1.6E-19C
based on my error (whatever that may be)
0 = 0.5mv^2 which means v=0, this doesn't seem correct.

Any suggestions?

 

[Char. Limit]

Shouldn't the charge of the electron be negative? Then you'd end up with

[tex]2x=.5mv^2[/tex]

Where x is the 1.6*10^-19...

 

[ryukyu]

Thanks,

I knew it was something simple that I had missed.