Electrostatic interaction energy example (jackson)

In summary, the conversation discusses solving an integral using the gradient identity and integrating by parts. The speaker is having trouble following the derivation and is looking for an easier way to evaluate the integral. The solution involves using the identity twice and then applying the divergence theorem and the fact that 1/\rho is the Green function for the 3d Laplace equation.
  • #1
rafaelpol
17
0

Homework Statement



I am trying to follow a derivation in Jackson - Classical Electrodynamics

Homework Equations



In equation 1.58 (2nd/3rd edition) of Jackson - Classical Electrodynamics he says that by using the fact that [itex]\mathbf{\rho} \cdot (\mathbf{\rho} +\mathbf{n})/ | \mathbf{\rho +n|}^{3} = \nabla_{\rho}(1/|\mathbf{\rho}+\mathbf{n}|), [/itex] the integral [itex] \int {\mathbf{\rho} \cdot (\mathbf{\rho} +\mathbf{n})/ \rho^3 | \mathbf{\rho +n|}^{3}} [/itex] can be easily shown to be equal to to [itex] 4\pi [\itex].

The Attempt at a Solution



I can't really follow on how to solve this integral once the fact mentioned above is known. I know how to solve the integral using spherical coordinates, but from what I have seen that does not follow from what Jackson said at all. I am just curious if there is an easier to evaluate the integral using the gradient identity.
 
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  • #2
You have a typo, but that's probably not the problem. We actually have to use the identity

[itex] \frac{\vec{\rho}+\hat{n}}{ | \vec{\rho}+\hat{n}|^3 } = - \nabla_\rho \left( \frac{1}{ | \vec{\rho}+\hat{n}|} \right)[/itex]

twice to rewrite

[itex]\int d^3\rho \frac{ \vec{\rho}\cdot ( \vec{\rho}+\hat{n}) }{ \rho^3 | \vec{\rho}+\hat{n}|^3} = \int d^3\rho \left[ \nabla_\rho \left( \frac{1}{ \rho} \right) \right] \cdot \left[ \nabla_\rho \left( \frac{1}{ | \vec{\rho}+\hat{n}|} \right) \right]. [/itex]

If we integrate by parts we find

[itex] \int d^3\rho \nabla_\rho\cdot \left[ \frac{1}{ | \vec{\rho}+\hat{n}|} \nabla_\rho \left( \frac{1}{ \rho} \right) \right]
-\int d^3\rho \frac{1}{ | \vec{\rho}+\hat{n}|} \nabla_\rho^2 \left( \frac{1}{ \rho} \right) . [/itex]

We can use the divergence theorem to show that the first, total derivative, term vanishes, while for the 2nd term, we use the fact that [itex]1/\rho[/itex] is the Green function for the 3d Laplace equation.
 
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Related to Electrostatic interaction energy example (jackson)

1. What is electrostatic interaction energy?

Electrostatic interaction energy is the potential energy that results from the interaction between electrically charged particles. It is a measure of the strength of attraction or repulsion between these particles.

2. How is electrostatic interaction energy calculated?

The electrostatic interaction energy between two charged particles can be calculated using Coulomb's law, which states that the energy is proportional to the product of the charges and inversely proportional to the distance between them.

3. What are some examples of electrostatic interaction energy in everyday life?

A common example is the attraction between positively and negatively charged objects, such as a comb and a piece of paper. Another example is the interaction between the charged particles in a battery, which produces the energy needed to power electronic devices.

4. What is the significance of electrostatic interaction energy in chemistry?

Electrostatic interaction energy plays a crucial role in determining the stability and reactivity of molecules. It helps explain the formation of ionic and covalent bonds between atoms, and the strength of these bonds is directly related to the electrostatic interaction energy between the participating atoms.

5. How does temperature affect electrostatic interaction energy?

As temperature increases, the kinetic energy of particles also increases, causing them to move faster and collide more frequently. This can disrupt the electrostatic interactions between charged particles, leading to a decrease in electrostatic interaction energy. However, in some cases, an increase in temperature can also lead to an increase in electrostatic interaction energy due to changes in the arrangement of particles.

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