- #1
Flucky
- 95
- 1
Homework Statement
A beam of 13.0 eV electrons is used to bombard gaseous hydrogen in ground state.
What photon energies will be emitted?
Homework Equations
ΔE = -13.6 ([itex]\frac{1}{n^{2}_{f}}[/itex] - [itex]\frac{1}{n^{2}_{i}}[/itex])
However hydrogen is in the ground state therefore n_i= 1:
ΔE = -13.6 ([itex]\frac{1}{n^{2}_{f}}[/itex] - 1)
The Attempt at a Solution
Rearranging the above equation I got n_f = 4.76.
Am I correct in saying "the photon can be emitted from a maximum energy state of n=4"?
I'm unsure how to word it.
WRT the initial question, it asks what photon energies will be emitted so would I have to write them all down?
ie
4[itex]\rightarrow[/itex]3 = 0.66 ev
4[itex]\rightarrow[/itex]2 = 2.55 ev
4[itex]\rightarrow[/itex]1 = 12.75 ev
3[itex]\rightarrow[/itex]2 = 1.89 ev
3[itex]\rightarrow[/itex]1 = 12.09 ev
2[itex]\rightarrow[/itex]1 = 10.2 ev