Electrical Circuit Exercise, .

[claudiadeluca]

Hi, I need help with the following exercise:

Homework Statement

We have a square circuit, with 4 capacitors, 1 on each side of the square, all with the same capacitance C. Calculate the total capacitance of the system of capacitors between the two diagonally opposite corners of the square, A and B.

This is how I solved it, could you tell me if it's right?

A ) 2 capacitors (from A to B ): they are in series
B ) 2 capacitors (from B to A): they are in series

A )1/Ceq = 1/C1 + 1/C2= 2/C --> A-Ceq=C/2
B )1/Ceq = 1/C3 + 1/C4= 2/C --> B-Ceq=C/2

Now A-Ceq and B-Ceq are in a parallel configuration:

C) Ceq = C/2 + C/2 = C

The total capacitance is equal to C?

Thank you.

 

[Astronuc]

You are correct.

 

[m2003]

Your solution looks correct. The total capacitance of the system is indeed equal to C, as you have shown by combining the series and parallel configurations of the capacitors. Good job!