Electric Force of Two Charges on Third Charge

In summary: The key is that the two charges are not located along the same axis, so their individual forces on q3 are not directly additive. In summary, the electric force exerted by charges q1=1.00*10^-9C and q2=2.00*10^-9C on charge q3=1.5*10^-9C, located at the origin, is 1.4*10^-4N. The individual forces are not directly additive because the charges are not located along the same axis.
  • #1
physgrl
138
0

Homework Statement



1. Charge q1= 1.00*10^-9C is located +0.01 m from the origin along the x-axis. Charge q2= 2.00*10^-9C is located +0.03 m from the origin. What is the electric force exerted by these two charges on a third charge, q3= 1.5*10^-9C, located at the origin?

a. 1.65*10^-4N

*b. 1.4*10^-4N

c. 4.4*10^-4N

d. 6.1*10^-4N

Homework Equations



F=kq1q2/r^2
Ftotal=F1+F2...Fn

The Attempt at a Solution



both charges q1 and q2 exert a repelling force in the same direction with different magnitudes on charge q3

Ftotal=Fq1+Fq2
Ftotal=kq1q3/r1-32+kq2q3/r2-32
Ftotal=kq3((q1/r1-32)+(q2/r2-32))
Ftotal=9x109*1.5x10-9(1.0x10-9/(.01)2)+(2.0x10-9/(.03)2))
Ftotal=1.65x10^-4

the answer key says it is supposed to be B but I get A...what am I doing wrong?
 
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  • #2
Are you sure that all three charges are located along the x-axis?
 
  • #3
It doesn't specify, so I assumed since the first one is along the x-axis the second one is two.
 
  • #4
physgrl said:
It doesn't specify, so I assumed since the first one is along the x-axis the second one is two.

Suppose, just for the sake of curiosity, that the second charge was located at y = +0.03m on the y-axis. What would the net force magnitude be on q3 at the origin?
 
  • #5
1.38x10^-4 so it was supposed to say it was at the y axis
 
  • #6
physgrl said:
1.38x10^-4 so it was supposed to say it was at the y axis

That would be my guess, yes.
 

Related to Electric Force of Two Charges on Third Charge

1. What is the electric force of two charges on a third charge?

The electric force of two charges on a third charge is the force exerted on the third charge due to the electric fields created by the two charges. It is calculated using Coulomb's Law, which states that the force is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.

2. How is the electric force affected by the magnitude of the two charges?

The electric force is directly proportional to the product of the two charges. This means that as the magnitude of the charges increases, the force between them also increases. For example, if both charges are doubled, the force between them will quadruple.

3. What happens to the electric force if the distance between the two charges is increased?

If the distance between the two charges is increased, the electric force decreases. This is because the force is inversely proportional to the square of the distance. As the distance increases, the force decreases at a faster rate.

4. Can the electric force of two charges on a third charge be attractive?

Yes, the electric force between two charges can be either attractive or repulsive. If the two charges have opposite signs (one positive and one negative), the force between them will be attractive. If the two charges have the same sign (both positive or both negative), the force between them will be repulsive.

5. How does the presence of other charges affect the electric force of two charges on a third charge?

The presence of other charges can affect the electric force between two charges on a third charge. If there are other charges nearby, their electric fields will interact with the electric fields of the two charges, potentially altering the overall force on the third charge. This is why it is important to consider all charges in the vicinity when calculating the electric force between two charges.

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