Electric Fields and Charges Fill in the blanks

In summary, the content discusses a series of questions about charges and their interactions with neutral objects. The first question involves a positive point charge being brought near a neutral conducting sphere, and the possible directions it could move in. The second question asks about the charge on a sphere after being connected to another sphere and then disconnected from a positively charged rod. The third question concerns the charge on an object suspended by a non-conducting thread when repelled by a positively charged glass rod. The fourth question involves a positively charged ball being brought close to a neutral isolated conductor and the effects of grounding it and then removing the ground connection. The final question is similar to the third, but with a negatively charged glass rod attracting the object instead. The correct answers
  • #1
JeffAndonuts
4
0

Homework Statement


[/B]

  1. Select the answers which complete the statements below (e.g., if answer A completes the first statement, and answer B the others, enter ABBBB).


    A) positive B) negative C) neutral D) cannot tell

    1. A positive point charge is brought near the outside surface of a neutral conducting sphere and released. The initial position of the point charge is on the positive x-axis and the sphere is centred on the origin. The point charge moves in the ____ x direction. (If the point charge does not move, select answer C.)
    2. Two neutral metal spheres are mounted on insulating supports. They are connected by a wire. A positively charged glass rod is brought near sphere 1. The wire connecting the spheres is removed and the charged rod is then taken away. Now the charge on sphere 1 is ____ .
    3. A positively charged glass rod repels an object suspended by a non-conducting thread. The charge on the object is ____ .
    4. A positively charged ball is brought close to a neutral isolated conductor. The conductor is then grounded, while the ball is kept close. If the ball is first taken away and then the ground connection is removed, the conductor has a ____ charge.
    5. A negatively charged glass rod attracts an object suspended by a non-conducting thread. The charge on the object is ____ .

Homework Equations


N/A

The Attempt at a Solution


i) This is the one which gave me the most trouble, but the way I see it, either it doesn’t move as the sphere is neutral, or it does move towards the sphere (Negative direction) as the electrons all move towards the point charge and they pull each other towards one another. So either B or C

ii) This is pretty straight forward. By connecting the two spheres, electrons can be transferred between them, and when the positively charged rod is brought next to sphere 1, all of the electrons in both spheres go towards it making sphere 1 negative and sphere 2 positive. The wire is then cut and the charged rod is removed, meaning sphere 1 will be negative. So B

iii) Again, pretty straight forward. Positively charged rod repels an object, so the object must be positively charged or it wouldn’t be repelled. So A

iv) This one also gave me a bit of trouble but I think I got it. A positively charge ball is brought close to a conductor, so the electrons go to the charged ball, it is then grounded, meaning electrons will come up from the ground to balance the positive side of the conductor. The charged is then removed so then electrons will flow out through the ground to bring the conductor back to being neutral, and the ground connection is then remove, so in the end, the conductor remains neutral. So C

v) Very similar to iii, this time it is a negatively charged rod that is attracting an object, therefore the object must be positive in order to be attracted to the negative charge. So AThe only issue is that I’ve tried all of those combinations, as well as all of the combinations with _BACA, with no success which means one or more of my answers must be wrong, but I cannot figure out which one(s) it could be. Any help would be much appreciated!
 
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  • #2
Hello Jeff&o, welcome to PF :smile:

I'm with you almost all the way. In case i) I don't understand why you hesitate between B and C.

And case v) is where I smell the proverbial rat. Compare with case i): in v) they mention an 'object', so you don't know if it's an insulator or a conductor. If assuming the former leads to a different conclusion than assuming the latter, there's no more A , and no B or C either ...

For the sake of other readers, let us know if it works -- or not !
 
  • #3
Thank you for the help! It ended up being BBACD, I guess the wording of the question got me, but again thank you! If you wouldn't mind, why can we not tell for v) but we can tell for iii), as the wording is almost identical, they just switch the charge on the rod and what happens to the object?
 
  • #4
JeffAndonuts said:
Thank you for the help! It ended up being BBACD, I guess the wording of the question got me, but again thank you! If you wouldn't mind, why can we not tell for v) but we can tell for iii), as the wording is almost identical, they just switch the charge on the rod and what happens to the object?

Switching the charge isn't important. Switching what happens to the object is. A charge can induce polarization in a neutral object and attract it. Can it repel it?
 
  • #5
Dick said:
Switching the charge isn't important. Switching what happens to the object is. A charge can induce polarization in a neutral object and attract it. Can it repel it?
That makes sense! Thanks!
 

Related to Electric Fields and Charges Fill in the blanks

What is an electric field?

An electric field is a region in which an electric charge experiences a force. It is created by the presence of other electric charges and can be either positive or negative.

How are electric fields and charges related?

Electric fields and charges are closely related as charges create electric fields and are also affected by them. Electric fields can be thought of as the "cause" of the force experienced by charges.

What is the equation for electric field strength?

The equation for electric field strength is E = F/q, where E is the electric field strength, F is the force experienced by a charge, and q is the magnitude of the charge.

What is the unit of electric field strength?

The unit of electric field strength is newtons per coulomb (N/C). This unit represents the force experienced by a charge of one coulomb in an electric field.

How can electric charges be distributed in an electric field?

Electric charges can be distributed in an electric field in three ways: positive charges can be distributed on one side and negative charges on the other, positive and negative charges can be mixed together, or charges can be uniformly distributed throughout the field.

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