- #1
thisischris
- 26
- 1
A VDGG is used to produce a large PD. The dome of the generator has a radios of 0.15m. It is charged and gets a PD between the dome and the Earth of 75kV.
The charged stored on it is : 5.0 x 10-6C
Answer: Use of E = Q/4∏εr0. 3.0 x 105
My attempt: E = kQ/r2 = 8.99 x 109 x 5.0 x 10-6 / 0.152 = 2.00 x 106
I get the provided answer if I don't square the 0.15. It also seems to be a potential print error as r is not squared in their equation as well as having a 0 as a sub-ponent(opposite of exponent?)... Could anyone share any light on this?
Much appreciated :)
The charged stored on it is : 5.0 x 10-6C
Answer: Use of E = Q/4∏εr0. 3.0 x 105
My attempt: E = kQ/r2 = 8.99 x 109 x 5.0 x 10-6 / 0.152 = 2.00 x 106
I get the provided answer if I don't square the 0.15. It also seems to be a potential print error as r is not squared in their equation as well as having a 0 as a sub-ponent(opposite of exponent?)... Could anyone share any light on this?
Much appreciated :)