- #1
IKonquer
- 47
- 0
I'm trying to show that the electric field for an infinitely large plate is
[tex]
E = \frac{\sigma}{2\epsilon_o}
[/tex]
I was wondering why you can only use a cylindrical gaussian surface and not a cube?
Thanks
[tex]
E = \frac{\sigma}{2\epsilon_o}
[/tex]
I was wondering why you can only use a cylindrical gaussian surface and not a cube?
Thanks