Electric Field Magnitude at Point P Inside a Charged Sphere

In summary, using Gauss' Law and the equation E = (kQr) / (a^3), we can find the magnitude of the electric field at point P, which is 1.12 * 10^5 V/m. However, when using the equation E = (Qr^3) / (epsilon,naut * a^3), we get a different result of 5.62E4 V/m. This discrepancy could be due to a mistake in the calculations or the use of different equations. It is recommended to take logical steps and properly determine the fraction of the total charge contained within the inner spherical volume before applying Gauss' Law.
  • #1
eurekameh
210
0
An insulating solid sphere of radius a = 1.2 m is uniformly charged with charge Q = 4.5 x 10^-6 C. Point P inside the sphere is at a distance r = 0.60 m from the sphere center C. What is the magnitude of the electric field at point P?

So I'm using Gauss' Law:

q,enc = Q[(pi * r^2)/ (pi * a^2)]

int(E dot dA) = q,enc / epsilon,naut
= Q[(pi * r^2)/ (pi * a^2)] / epsilon,naut

E * (pi * r^2) = Q(r^2 / a^2) / epsilon,naut

Thus, E = (Q) / (pi * epsilon,naut * a^2) = 1.12 * 10^5 V/m.

This doesn't seem to be the answer. Anyone know what I did wrong?
 
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  • #2
Volume varies as the cube of the radius.
 
  • #3
Now I'm doing E * pi * r^2 = (Qr^3) / (epsilon,naut * a^3), but E is turning out to be 5.62E4 V/m, which is 4 times the correct answer.
 
  • #4
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?
 
  • #5
r^3 / a^3
 
  • #6
gneill said:
Rather than trying to do everything at once, why not take logical steps? First, what fraction of the total charge Q is contained in the inner spherical volume of radius r?

eurekameh said:
r^3 / a^3

Okay, so given that you know the total charge Q, you now know the fraction of that charge that's within the spherical region with radius r.

Now, given a charge q within that sphere of radius r, what's the resulting electric field at distance r from its center?
 
  • #7
E = (Qr) / (pi * a^3)
 
  • #8
Edit:
E = (Qr) / (pi * a^3 * epsilon,naut)
 
  • #9
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.
 
  • #10
eurekameh said:
Actually, E = kq / r^2 = (kQr) / (a^3) works, but I'm trying to use Gauss' Law.

So choose your Gaussian surface and write Gauss' law for for it. You'll find that you need the total charge enclosed by the surface (done above), and the volume of the Gaussian sphere (done above). I suppose it's just a matter of putting the steps in an order that shows the appropriate progression :smile:
 

Related to Electric Field Magnitude at Point P Inside a Charged Sphere

What is an electric field?

An electric field is a physical quantity that describes the influence that a charged object has on other charged objects in its vicinity. It is a vector quantity, meaning it has both magnitude and direction.

What is the formula for calculating electric field magnitude at a point inside a charged sphere?

The formula for calculating electric field magnitude at a point inside a charged sphere is E = kQr / R^3, where E is the electric field magnitude, k is Coulomb's constant (9x10^9 N*m^2/C^2), Q is the charge of the sphere, r is the distance from the center of the sphere to the point, and R is the radius of the sphere.

How does the electric field magnitude change as you move further away from the center of the charged sphere?

The electric field magnitude decreases as you move further away from the center of the charged sphere. This is because the electric field follows an inverse square law, meaning that it decreases with the square of the distance from the source charge.

Can the electric field magnitude at a point inside a charged sphere be negative?

Yes, the electric field magnitude at a point inside a charged sphere can be negative. This would occur if the sphere has a net negative charge, and the point is located in a direction opposite to the direction of the electric field vector.

What is the relationship between the electric field magnitude and the charge of the sphere?

The electric field magnitude is directly proportional to the charge of the sphere. This means that as the charge of the sphere increases, the electric field magnitude at a point inside the sphere also increases. This relationship is described by the formula E = kQ / R^2, where Q is the charge of the sphere.

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