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jmz34
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A dielectric cylinder of radius 'a' and permittivity 'e' is placed in a uniform field Eo with the direction of field perpendicular to the axis of the cylinder, find the E field (Ei) inside the cylinder. I CAN DO THIS PART OF THE QUESTION FINE. It turns out that:
Ein=2Eo/(1+e)
Next, consider the situation where the cylinder is tipped so that its axis makes an angle phi to Eo, find a new expression for Ein.
I know I'm supposed to use the continuity conditions that D-perpendicular and E-parallel are continuous at the interface, but I'm confused as to how to go about doing this. I've come up with the equations Eosin(theta1)=Eintsin(theta2) where I think theta1=90-phi.
Thanks in advance.
Ein=2Eo/(1+e)
Next, consider the situation where the cylinder is tipped so that its axis makes an angle phi to Eo, find a new expression for Ein.
I know I'm supposed to use the continuity conditions that D-perpendicular and E-parallel are continuous at the interface, but I'm confused as to how to go about doing this. I've come up with the equations Eosin(theta1)=Eintsin(theta2) where I think theta1=90-phi.
Thanks in advance.