- #1
nimadh
- 6
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Hey,
Completing AP Problems, I ran into a puzzling answer.
Basically, there was a conducting sphere with charge Q on it and radius R1, and then around it two hollow hemispheres were placed (forming a spherical capacitor) which had no charge, with Radius R2 at the inner edge and R3 at the outer edge.
Basically, the problem asked for the electric field
- a) less than R1
- b) between R1 and R2
- c) between R2 and R3
- d) greater than R3
The answers were given as:
- a) zero
- b) kQ/R^2
- c) zero
- d) zero
I understand a, b, and c, but I could not understand why d is zero. Wouldn't the enclosed charge according to Gauss's law be the charge on the inner sphere? Or would the outer conducting surface somehow neutralize the charge?
Keep in mind that this is an actual Collegeboard Question, so the answers are certainly right (at least using basic physics). The Question is Physics C 1999 #1 for Electromagnetism.
Thanks!
Completing AP Problems, I ran into a puzzling answer.
Basically, there was a conducting sphere with charge Q on it and radius R1, and then around it two hollow hemispheres were placed (forming a spherical capacitor) which had no charge, with Radius R2 at the inner edge and R3 at the outer edge.
Basically, the problem asked for the electric field
- a) less than R1
- b) between R1 and R2
- c) between R2 and R3
- d) greater than R3
The answers were given as:
- a) zero
- b) kQ/R^2
- c) zero
- d) zero
I understand a, b, and c, but I could not understand why d is zero. Wouldn't the enclosed charge according to Gauss's law be the charge on the inner sphere? Or would the outer conducting surface somehow neutralize the charge?
Keep in mind that this is an actual Collegeboard Question, so the answers are certainly right (at least using basic physics). The Question is Physics C 1999 #1 for Electromagnetism.
Thanks!