Elastic Collision Momentum Question

In summary, the problem says that the blocks separate after collision. However, the original problem does not imply an elastic collision, so the blocks actually separate in this case.
  • #1
s8on95
13
0
Same question as this link except my teacher changed the numbers. 1996-B No.1 part C

http://lodischool.tripod.com/dovesol/DOVE96SOL.pdf

Velocity of Bock A=4v0




2. mv+mv=mv+mv



3. I understand how to do the question in the pdf file. However, I don't understand how the concept applies in my teacher's version. Solving for the velocity you get 2.5 m/s which is supposed to be the answer. However, the question says "the objects separate after collision". Wouldn't they not separate if they both travel 2.5 m/s after the collision? I don't understand how this is possible.
 
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  • #2
Is the initial speed of block A the only thing the teacher changed? If so, then it is an inelastic collision.
 
  • #3
So would this problem be "impossible" to do then? If block B continues at 2.5, then it'd be inelastic but it says they separate. (I got this problem "wrong" on a test btw)
 
  • #4
Again, if the only thing the teacher changed is the initial velocity of block A from 3v0 to 4v0, then a speed of 2.5v0 for B implies a speed of 2.5v0 for A as well. You say you got that question wrong. Do you know what the right answers are?
 
  • #5
I got the problem wrong because I made up random numbers. What I did was wrong. The right answer was that block A continued at a speed of 2.5 V0. My dilemma is that would this not imply an inelastic collision if they continued at equal velocities?
 
  • #6
Nowhere in the problem was an elastic collision implied, either in the original, or the altered problem.
 
  • #7
Sorry, wrong wording. I mean to ask how is it possible they can separate when they go at the same velocity after collision?
 
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  • #8
They haven't separated. You're getting too caught up on the wording and not on the physics.
 
  • #9
The problem clearly says the blocks separate after collision in Part C.
 
  • #10
Your teacher copied the problem and didn't change the wording. No physics has been changed. You are just obsessing with the wording of a badly worded problem.
 
  • #11
But that is exactly my problem. Shouldn't it NOT BE POSSIBLE for the physics to be possible with the given wording? If I were given the same problem as the link, I could've done it with ease. I understand the physics concepts/math no problem. When I took the test though I just thought this was a weird scenario.

It is predicted an inelastic collision with 2.5 m/s of both of them together

What happens is they actually separate and still both go at 2.5 m/s?

During the test I calculated and was going to put 2.5 m/s but this would've implied they didn't separate. That is why I ended up becoming confused and doing a bunch of random weird stuff. I understand the mathematical physics but my problem is exactly with obsessing over the wording. It just shouldn't make sense!
 
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  • #12
I will state it again. THEY DID NOT SEPARATE. Your teacher changed the numbers but did not change the wording. This happens all the time, to the best and the worst teachers. The calculations you did show that it was going at 2.5v0 (not 2.5m/s, you were never given an actual speed), and I've shown you that your calculations are correct, so that is the speed it was moving with. If you had used 2.5m/s you would have gotten the question right. If you still have questions about the wording of the problem, you need to take it up with your teacher, not Physics Forums.
 
  • #13
Okay then. I shall consult my teacher (another student did and I think she was said to respond with something along the lines of "they just separate"). Thanks for the help!
 
  • #14
Let us know what your teacher says. I'm really curious.
 

Related to Elastic Collision Momentum Question

1. What is an elastic collision?

An elastic collision is a type of collision where both the total kinetic energy and the total momentum of the system are conserved. This means that the objects involved in the collision bounce off each other without any loss of energy or momentum.

2. How is momentum conserved in an elastic collision?

In an elastic collision, momentum is conserved because the total momentum of the system before the collision is equal to the total momentum of the system after the collision. This is due to the fact that the forces acting on the objects involved are equal and opposite, resulting in no overall change in momentum.

3. What is the equation for calculating momentum in an elastic collision?

The equation for calculating momentum in an elastic collision is: P = m1v1 + m2v2, where m1 and m2 are the masses of the objects involved and v1 and v2 are their velocities before the collision.

4. Can the direction of momentum change in an elastic collision?

Yes, the direction of momentum can change in an elastic collision. This is because the objects involved in the collision can have different masses and velocities, resulting in a change in direction of their combined momentum.

5. What are some real-world examples of elastic collisions?

Some real-world examples of elastic collisions include billiard balls colliding on a pool table, two cars colliding and bouncing off each other, and a tennis ball bouncing off a wall. These collisions are considered to be elastic because they do not result in any loss of energy or momentum.

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