Efficiently Factor Polynomials: Solving 36(2x-y)^2 - 25(u-2y)^2

In summary, to factor the expression 36(2x-y)^2 - 25(u-2y)^2, you can start by noticing that it is the difference of two squares. For the expression (a^2 - ab)^2 -8b^2(a^2 - ab) + 12b^4, you can factor out (a^2 - ab) and then use the factoring method for expressions in the form ax^2+bxy+cy^2. Alternatively, you can let X = (a^2 - ab) and Y = b^2, and then solve for X and Y before substituting back into the original expression.
  • #1
richievuong
35
0
Factoring polynomials(2nd problem)

Factor:

36(2x-y)^2 - 25(u-2y)^2

Having trouble where to start...should I expand out?
 
Last edited:
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  • #2
richievuong said:
Factor:

36(2x-y)^2 - 25(u-2y)^2

Having trouble where to start...should I expand out?

Is that u and u, or is that suppose to be an x
 
  • #3
You can start by noticing that that is the difference of two squares.
 
  • #4
Yeah its a U, got it figured out now.

I have another one that I'm having trouble with:

(a^2 - ab)^2 -8b^2(a^2 - ab) + 12b^4

I tried factoring the a^2-ab out

= (a^2-ab)[-8b^2 + (a^2-ab)] + 12b^4

Tried a couple methods none really worked out...what should be my next step? Should i factor a^2-ab to a(a-b)?
 
Last edited:
  • #5
Do you know how to factor ax^2+bxy+cy^2? Because this expression is in that form.
 
  • #6
richievuong said:
Yeah its a U, got it figured out now.

I have another one that I'm having trouble with:

(a^2 - ab)^2 -8b^2(a^2 - ab) + 12b^4

I tried factoring the a^2-ab out

= (a^2-ab)[-8b^2 + (a^2-ab)] + 12b^4

Tried a couple methods none really worked out...what should be my next step? Should i factor a^2-ab to a(a-b)?
Make

(a^2 - ab)=X
AND
b^2=Y

Therefore, X^2-8xy+12y^2

Then solve and sub back in.
 

Related to Efficiently Factor Polynomials: Solving 36(2x-y)^2 - 25(u-2y)^2

What is the purpose of factoring polynomials?

The purpose of factoring polynomials is to simplify and solve mathematical expressions by breaking them down into smaller, equivalent parts.

How do you efficiently factor polynomials?

To efficiently factor polynomials, you can use various techniques such as grouping, factoring by grouping, the difference of squares formula, and the quadratic formula.

What are the steps to factoring 36(2x-y)^2 - 25(u-2y)^2?

The first step is to factor out the greatest common factor, which in this case is 36. This leaves us with 36[(2x-y)^2 - (u-2y)^2]. Next, we can use the difference of squares formula to factor the expression within the parentheses. This gives us 36[(2x-y+u-2y)(2x-y-u+2y)]. Finally, we can simplify the expression to get the final factored form: 36[(2x-u)(x-3y)].

How do you check if a polynomial is factored correctly?

You can check if a polynomial is factored correctly by multiplying the factored form back together and comparing it to the original expression. The two should be equivalent.

What are the common mistakes to avoid when factoring polynomials?

Some common mistakes to avoid when factoring polynomials include forgetting to check for a common factor, not applying the correct factoring formula, and making errors when simplifying the factored expression.

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