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- #1

- Jan 29, 2012

- 661

Here is a link to the question:How do I evaluate the integral dx/(x^(2/3)) from -3 to 3?

What I did was, so for the integrand f(x)=1/(x^(2/3)) it's only continuous from (0, infinity), it's discontinuous at x=0, so I set up the integral as the limit as b approaches 0 from the right of the same integrand, so my answer was 3*(3)^(1/3) but that's wrong. Please help me?

Improper integral help? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.