E field outside of two non conductive shells?

In summary, the problem involves two non-conductive shells with different radii and charges. The electric fields for different regions are as follows: for r < r1, the electric field is 0; for r1 < r < r2, the electric field is given by q1 / 4*pi*epsilon_not*r^2; for r > r2, the electric field is unclear as the charge enclosed is not specified. It is not significant for the shells to be non-conductive as the same equations and principles apply for conductive shells as well.
  • #1
jdub129
1
0

Homework Statement



Two non conductive shells surround each other, with radius r1, r2 and charges q1, q2 respectively.
Find electric fields for E(r < r1), E(r1 < r < r2), E(r > r2)

r1 is the inner shell, r2 is the outer shell (r1 < r2)

Homework Equations



I'm using gauss' law

flux = E * A = q_enclosed / epsilon_not

The Attempt at a Solution



E(r < r1) = 0
E(r1 < r < r2) = q1 / 4 * pi * episolon_not * r^2

I'm confused on E(r > r2), what is the charged enclosed for two surrounding non conductive shells?
Would I add up the charge from both (q1 + q2)? or would it only be the charge on the outer shell q2?

I don't know what is significant about the shells being "non conductive" vs "conductive" what is the difference?

please respond.
 
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  • #2
q1 + q2

No difference with conductive shells.
 

Related to E field outside of two non conductive shells?

1. What is the purpose of using non-conductive shells in an electric field?

The non-conductive shells are used to contain and control the electric field, preventing it from interacting with the surrounding environment.

2. How does the electric field behave outside of two non-conductive shells?

Outside of the shells, the electric field follows the inverse square law, decreasing in strength as the distance from the shells increases.

3. Can the electric field outside of the shells be affected by the material of the shells?

Yes, the electric field can be affected by the material of the shells. Conductive materials will cause the electric field to be distorted, while non-conductive materials will contain the electric field.

4. Is the electric field outside of the shells uniform?

No, the electric field outside of the shells is not uniform. The field lines curve and distort due to the presence of the shells, creating areas of higher and lower electric field strength.

5. How can the electric field outside of the shells be calculated?

The electric field outside of the shells can be calculated using Gauss's Law, which relates the electric field to the charge enclosed by a surface. The charge on the shells and the distance from the shells will determine the strength of the electric field at a specific point.

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