Drawing free body diagrams (torque; rotational motion)

In summary: So the force has to have a component which is perpendicular to the beam. In summary, the problem involves a 500-N person standing 2.5 m from a wall with a horizontal beam attached to the wall. The beam is 6 m long and weighs 200N. A cable attached to the free end of the beam makes a 45 degree angle with the horizontal and is attached to the wall. The force R in the solution refers to the force exerted by the pivot at an angle theta to keep the beam in place. This force must have a vertical component to keep the beam from falling down.
  • #1
Janet1234
1
0

Homework Statement


A 500-N person stands 2.5 m from a wall against which a horizontal beam is attached. The beam is 6 m long and weighs 200N (see diagram below). A cable attached to the free end of the beam makes an angle of 45 degrees to the horizontal and is attached to the wall.
ph1.jpg
ph2.jpg

Homework Equations


I'm not sure what is the force R mean in the answer, and why is it pointing in an angle theta instead of perpendicular to the wall.

The Attempt at a Solution


I drew a normal force at the end of the beam perpendicular to the wall, which is apparently not the right answer haha.
 
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  • #2
Janet1234 said:

Homework Statement


A 500-N person stands 2.5 m from a wall against which a horizontal beam is attached. The beam is 6 m long and weighs 200N (see diagram below). A cable attached to the free end of the beam makes an angle of 45 degrees to the horizontal and is attached to the wall.

Homework Equations


I'm not sure what is the force R mean in the answer, and why is it pointing in an angle theta instead of perpendicular to the wall.

The Attempt at a Solution


I drew a normal force at the end of the beam perpendicular to the wall, which is apparently not the right answer haha.

Hi Janet, welcome to Physics Forums!
The beam is attached to the wall by a pivot, and the pivot can act with force at an angle.

upload_2017-3-17_5-3-7.png
 
  • #3
+1

Its not hard to see why that force must have a vertical component - if it didn't the beam would fall down.
 

Related to Drawing free body diagrams (torque; rotational motion)

1. What is a free body diagram?

A free body diagram is a visual representation of the forces acting on an object in a given situation. It is used to analyze and understand the motion and equilibrium of the object.

2. How do you draw a free body diagram?

To draw a free body diagram, you first need to identify all the forces acting on the object. Then, draw a dot or a box to represent the object and label it with its mass. Next, draw arrows to represent the magnitude and direction of each force, making sure to label them. Finally, make sure that the forces are drawn in the correct relative positions and orientations.

3. What is torque in a free body diagram?

Torque is the measure of the turning or rotational force on an object. It is calculated by multiplying the force by the distance from the pivot point to the point where the force is applied.

4. How do you represent torque in a free body diagram?

To represent torque in a free body diagram, draw an arrow or line perpendicular to the force and label it with the distance from the pivot point. The direction of the torque is determined by the direction of the force and the direction of rotation.

5. What is the purpose of drawing a free body diagram for rotational motion?

Drawing a free body diagram for rotational motion helps to visualize and understand the forces and torques acting on an object in rotational motion. It also allows for the application of equations and principles, such as Newton's laws of motion and the concept of torque, to solve for unknown quantities and predict the motion of the object.

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