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#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

I would like if someone could confirmed if I did understand correct.

In a ON-system we dont use \(\displaystyle u*v=|u||v|\cos\theta\) cause In a ON-system the \(\displaystyle \theta=\frac{\pi}{2}\) so \(\displaystyle \cos(\frac{\pi}{2})=0\)

Regards

\(\displaystyle |\pi\rangle\)