Does the Electron's Magnetic Field Possess Higher-Order Poles?

In summary: For this conversation, we can summarize by saying that the magnetic field produced by a single electron is considered to be an ideal dipole and does not possess higher-order poles. However, if the electron had an additional degree of freedom, such as a "quadrupole spin," the energy levels would be quadruply degenerate. While it is possible to calculate the magnetic field of a permanent magnet by summing up little dipoles, this is not always an accurate representation as real magnets can behave in ways that contradict this view. One explanation for this is that the iron or neodymium in a permanent magnet is composed of nonparallel dipole fields in different size regions, which can reorient under the influence of an outside magnetic field.
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Is the magnetic field produced by a single electron an ideal dipole, or does it posses higher-order poles?
 
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  • #2
Throughout quantum mechanics we assume that besides position and momentum, the only other degree of freedom an electron has is its spin--which as you said generates a magnetic dipole field. It possesses no "quadrupole spin" or higher-order degree of freedom.

Let's imagine the electron did have an additional degree of freedom akin to a spin, take the most basic case of a "quadrupole spin" of 1/2, such that it can have a quadrupole moment of "up" or "down" in addition to a dipole moment of "up" or "down." For shorthand let's write "up" and "down" as + and -. (Also assume that this particle is still a fermion--this is actually a nontrivial assumption.) Therefore the electron with normal spin 1/2 and "quadrupole spin" 1/2 would have one of the following spin states: |++>, |+->, |-+>, or |-->. If this were the case, then a hamiltonian that doesn't depend on the magnetic dipole or quadrupole moments would have quadruply degenerate energy levels rather than the usual double. For example, instead of a single S orbital permitting two electrons, it would permit four electrons when we include the quadrupole-1/2 degree of freedom, one each corresponding to |++>, |+->, |-+>, and |-->.
 
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  • #3
I see, thanks. So can you calculate the magnetic field of a permanent magnet by just summing up little dipoles and integrating over the volume of the magnet? (with the idealization that on average all the dipoles are aligned in the same direction)
 
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Well, if you buy into the approximation that the permanent magnet is basically composed of a bunch of little parallel dipoles, then yes you could do that. Magnetic fields do obey the superposition principle. I'd guess that's a decent approximation for certain kinds of magnets. However, most real magnets behave in ways that would contradict that view. For example, take two ordinary bar magnets and position them side-to-side like this
|N| |N|
|S| |S|
(Unlike most of the things I talk about on PF, this is actually something you can do and you can't really figure out the real answer in your head). You'll notice that once you push them close enough together, the magnets snap together! This is because they induce quadrupole moments on one another--something that you wouldn't find by superposing a bunch of parallel dipole fields. Also, this would contradict the normal view of a magnet as a solenoid, since oppositely flowing currents repel one another.

One way to understand that experiment is by thinking of the iron (or neodymium, etc.) as composed of many different size regions (grains) each with different nonparallel dipole fields, which can reorient themselves under the influence of an outside magnetic field.
 
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  • #5


The magnetic field produced by a single electron is not an ideal dipole, but rather a combination of higher-order poles. This is due to the fact that the electron has a non-zero spin, which creates additional magnetic moments and therefore, higher-order poles in the magnetic field. Additionally, the electron also has an intrinsic magnetic moment, known as the spin magnetic moment, which contributes to the complex nature of its magnetic field. Therefore, while the magnetic field of a single electron can be approximated as a dipole, it is important to consider the presence of higher-order poles in order to accurately describe and understand its behavior.
 

Related to Does the Electron's Magnetic Field Possess Higher-Order Poles?

1. What is the Dipole Field of the Electron?

The dipole field of the electron is a phenomenon in which the electron has a positive charge at one end and a negative charge at the other, creating an electric dipole. This dipole field influences the behavior of other particles and is an essential aspect of electromagnetism.

2. How is the Dipole Field of the Electron created?

The dipole field of the electron is created due to the distribution of charges within the electron. The negatively charged particles, called electrons, are located on the outer edge of the electron, while the positively charged particles, called positrons, are located at the center.

3. What is the strength of the Dipole Field of the Electron?

The strength of the dipole field of the electron is determined by the separation between the positive and negative charges within the electron. The stronger the separation, the stronger the dipole field.

4. How does the Dipole Field of the Electron affect other particles?

The dipole field of the electron can influence the behavior of other particles, especially those with opposite charges. It can attract particles with positive charges and repel particles with negative charges.

5. Can the Dipole Field of the Electron be manipulated?

Yes, the dipole field of the electron can be manipulated by applying an external electric field. This can change the orientation and strength of the dipole field, which can have various effects on other particles and their behavior.

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