Does Adding a Constant to the Hamiltonian Affect Quantum System Dynamics?

In summary, the conversation discusses the treatment of the hydrogen molecule in relation to the exchange interaction and the addition of a constant term to the Hamiltonian. It is noted that in classical physics, adding a constant does not change the physical picture, but in wave-mechanics it does shift the frequency of the wavefunction. The question is then raised about the effect of these constant terms on the physical system, to which the answer is "no" as it only results in a time-dependent phase or does not change the evolution of operators.
  • #1
MadRocketSci2
48
1
So, I was reading about the exchange interaction, and trying to work out what it referred to, and came across something strange in the treatment of the hydrogen molecule (I think it was on wikipedia):

The hamiltonian given for the system included a term e2/(4πε0 * Rab) for the repulsion between nuclei a and b, even though the wave equation was only for the motion of the electrons, and the nuclei are treated as fixed.

In classical physics, you can add a constant to the hamiltonian, and it doesn't change the physical picture of what is being described. It doesn't matter where zero reference energy is, in terms of the forces on the system.

In wave-mechanics, however, adding a constant to the hamiltonian does shift the frequency of the wavefunction, if not the spatial form of the stationary states. This leads me to wonder about the equivalence of the physical picture for non-stationary states. (time varying states, transient states when the electron cloud is in transition between two energy levels, behavior of free particles, etc.)

(Thinking back to optics:) If you have something like a beam focusing down to a focus point, then diverging - the minimum spot size for a given initial aperture is very much dependent on the wavelength, and here the wavelength seems to be dependent on this reference energy that (at least in classical mechanics) should be arbitrary.

So: Do these constant terms added to the hamiltonian, and shifted frequencies change the system physically? (ie, the way the squared magnitude of the wavefunction moves around, Pauli velocities/currents, etc)?
 
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  • #2
The short answer to your question is "no".

If you are using the Schrödinger representation, where the states evolve, it would simply correspond to adding an additional (and equal) time dependent phase to all states and only phase differences are relevant.

If you are using the Heisenberg representation, where operators evolve, the evolution is given by the commutator of the operator and the Hamiltonian. Since anything commutes with a constant (something proportional to the identity operator), adding a constant does not change the evolution of operators.
 

Related to Does Adding a Constant to the Hamiltonian Affect Quantum System Dynamics?

1. What is a quantum Hamiltonian?

A quantum Hamiltonian is a mathematical operator that describes the total energy of a quantum system. It takes into consideration the kinetic energy and potential energy of the particles in the system and is used to calculate the time evolution of the system.

2. How is the quantum Hamiltonian different from the classical Hamiltonian?

The quantum Hamiltonian takes into account the wave-like nature of particles in the quantum system, while the classical Hamiltonian only considers the particle-like behavior. Additionally, the quantum Hamiltonian includes operators for position and momentum, rather than just variables.

3. What is the importance of the quantum Hamiltonian in quantum mechanics?

The quantum Hamiltonian is a fundamental concept in quantum mechanics as it is used to describe the behavior and evolution of quantum systems. It allows us to make predictions about the behavior of particles at the quantum level and has applications in fields such as quantum computing and quantum chemistry.

4. How is the quantum Hamiltonian calculated?

The quantum Hamiltonian is calculated by taking the sum of the kinetic energy and potential energy operators for all particles in the system. The kinetic energy operator is calculated using the momentum operator and the potential energy operator is determined by the physical properties of the system.

5. Can the quantum Hamiltonian be solved exactly?

In most cases, the quantum Hamiltonian cannot be solved exactly. Instead, approximations and numerical methods are used to calculate the behavior of the quantum system. However, for certain simple systems, such as a single particle in a box, the quantum Hamiltonian can be solved exactly.

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